Iterating formula until value converges
조회 수: 3 (최근 30일)
이전 댓글 표시
So the problem is i would like to use a while loop to iterate an equation by substituting values calculated in the last iteration into the next iteration until the value epsilon_conv converges to some small number such as 0.001. Below is the code so far, i am able to find the first iteration ok but then i'm not sure how to sub the new values in and use the equation for epsilon_conv with the old and new beta values to find convergence. Thanks in advance.
clear all;
syms Sy Pa b h Pb l
f=(Sy-(Pa/(b*h)))-(6*Pb*l/(b*h^2)); % master equation
dSy=diff(f,Sy); % f diffirentiated wrt Sy
dPa=diff(f,Pa); % f diffirentiated wrt Pa
db=diff(f,b); % f diffirentiated wrt b
dh=diff(f,h); % f diffirentiated wrt h
dPb=diff(f,Pb); % f diffirentiated wrt Pb
dl=diff(f,l); % f diffirentiated wrt l
Sy=4000; % values used in first iteration
Pa=2500;
b=2;
h=5;
Pb=900;
l=16;
Sys=400; % values used in first iteration
Pas=250;
bs=0.2;
hs=0.5;
Pbs=90;
ls=1.6;
epsilon=1;
epsilon_conv=0.001;
i=1;
while epsilon>epsilon_conv
if i=1
oldbeta=1;
else
DSy=subs(dSy); % Substituting values into diffirentiated equations
DPa=subs(dPa);
Db=subs(db);
Dh=subs(dh);
DPb=subs(dPb);
Dl=subs(dl);
fnorm=subs(f);
beta1=fnorm/sqrt((DSy*Sys)^2+(DPa*Pas)^2+(Db*bs)^2+(Dh*hs)^2+(DPb*Pbs)^2+(Dl*ls)^2); % defining beta
a11=-(DSy*Sys)/sqrt((DSy*Sys)^2+(DPa*Pas)^2+(Db*bs)^2+(Dh*hs)^2+(DPb*Pbs)^2+(Dl*ls)^2);
a21=-(DPa*Pas)/sqrt((DSy*Sys)^2+(DPa*Pas)^2+(Db*bs)^2+(Dh*hs)^2+(DPb*Pbs)^2+(Dl*ls)^2);
a31=-(Db*bs)/sqrt((DSy*Sys)^2+(DPa*Pas)^2+(Db*bs)^2+(Dh*hs)^2+(DPb*Pbs)^2+(Dl*ls)^2);
a41=-(Dh*hs)/sqrt((DSy*Sys)^2+(DPa*Pas)^2+(Db*bs)^2+(Dh*hs)^2+(DPb*Pbs)^2+(Dl*ls)^2);
a51=-(DPb*Pbs)/sqrt((DSy*Sys)^2+(DPa*Pas)^2+(Db*bs)^2+(Dh*hs)^2+(DPb*Pbs)^2+(Dl*ls)^2);
a61=-(Dl*ls)/sqrt((DSy*Sys)^2+(DPa*Pas)^2+(Db*bs)^2+(Dh*hs)^2+(DPb*Pbs)^2+(Dl*ls)^2);
Sy=Sy+(beta1*Sys*a11); %%% new value of Sy etc. to be used in calculation of next iteration
Pa=Pa+(beta1*Pas*a21);
b=b+(beta1*bs*a31);
h=h+(beta1*hs*a41);
Pb=Pb+(beta1*Pbs*a51);
l=l+(beta1*ls*a61);
Sys=(x12-Sy)/Sys; %% new value of Sys etc. to be used in calculation of next iteration
Pas=(x22-Pa)/Pas;
bs=(x32-b)/bs;
hs=(x42-h)/hs;
Pbs=(x52-Pb)/Pbs;
ls=(x62-l)/ls;
epsilon_conv=(oldbeta-newbeta)/newbeta %% number that must converge to 0.001
댓글 수: 0
답변 (1개)
Ameer Hamza
2020년 4월 9일
Overall the idea of your code is correct, but there are a few syntax issues.
The line
if i=1
is incorrect, use i==1 as condition.
I guess you just want to run the line old_beta = 1 once in first iteration. If yes, then you should change the variable i so that its is not repeated again
if i==1
oldbeta=1;
i = 2;
else
Also in these lines
Sys=(x12-Sy)/Sys; %% new value of Sys etc. to be used in calculation of next iteration
Pas=(x22-Pa)/Pas;
bs=(x32-b)/bs;
hs=(x42-h)/hs;
Pbs=(x52-Pb)/Pbs;
ls=(x62-l)/ls;
valuesof x12, x22, x32, ..., x62 are not defined. Define them before use.
Since you are using symbolic variables, your code will run slow. If fast processing is required, study about matlabFunction() and function handless.
댓글 수: 2
Ameer Hamza
2020년 4월 9일
abreg123, in first iteration, the condition for if block become true and only this lines runs
oldbeta=1;
Following lines don't run in first iteration
DSy=eval(subs(dSy)); % Substituting values into diffirentiated equations
DPa=eval(subs(dPa));
Db=eval(subs(db));
Dh=eval(subs(dh));
DPb=eval(subs(dPb));
Dl=eval(subs(dl));
fnorm=eval(subs(f));
beta1=fnorm/sqrt((DSy*Sys)^2+(DPa*Pas)^2+(Db*bs)^2+(Dh*hs)^2+(DPb*Pbs)^2+(Dl*ls)^2); % defining beta
i=i+1;
so the value of Dsy is not defined and it gives error on first iteration.
Also note that the value of the variable i will never change in your code because the initial value of i is 1, the if-condition becomes true. But the value of i does not change, because the else block never run. Also, note that beta is not defined in your code. Can you explain the program logic, maybe I can suggest an easier approach.
참고 항목
카테고리
Help Center 및 File Exchange에서 Calculus에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!