Perform AND operations with multiple matrices

조회 수: 2(최근 30일)
KostasK 2020년 4월 9일
댓글: KostasK 2020년 4월 9일
Hi all,
I am performing AND operations with multiple matrices, where I have a cell array M={1x3} containing three matrices of arbitrary dimensions, and a vector c=[1x3] containing three numbers. And with those I have to perform the below operation:
M = {rand(15), rand(15), rand(15)} ;
c = rand(1, 3) ;
i = find(M{1} == c(1) & M{2} == c(2) & M{3} == c(3)) ;
Since the second dimension of M and c are set to vary to any number (i.e. it could be 4,5,6, etc.), I was wondering wether there was a way to perform the AND (&) operation in a way which could account for the above, instead of manually ammending the code every time.
Thanks for your response in advance,

채택된 답변

Walter Roberson
Walter Roberson 2020년 4월 9일
편집: Walter Roberson 2020년 4월 9일
M = {rand(15), rand(15), rand(15)} ;
c = rand(1, 3) ;
cc = num2cell(c);
fold(@and, cellfun(@(V,C) V == C, M, cc, 'uniform', 0))
  댓글 수: 1
KostasK 2020년 4월 9일
This one works well!

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추가 답변(2개)

Andrei Bobrov
Andrei Bobrov 2020년 4월 9일
i = find(all(cat(3,M{:}) == reshape(c,1,1,[]),3));

Alexandra McClernon Ownbey
Alexandra McClernon Ownbey 2020년 4월 9일
편집: Alexandra McClernon Ownbey 2020년 4월 9일
This may not be the most efficient way, but it works. I stored everything in a logical and then compared the k-dimension in that logical. I also modified to randi with a range just so I can test it
M = {randi([-1,1],15,15), randi([-1,1],15,15), randi([-1,1],15,15)} ;
c = randi(1, 3) ;
ix = false(length(M{1}(1,:)),length(M{1}(:,1)),length(c));
for j = 1:length(c)
ix(:,:,j) = M{j} == c(j);
[l,m,n] = size(ix);
k = 1;
for i = 1:l
for j = 1:m
if all(ix(i,j,:))
row(k) = i;
col(k) = j;
k = k+1;
the locations of where c = M are located in row and col.

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