skip the value in for-loop

a = 27;
c = 11;
m = 54;
x(1)=2;
for i=2:25
    x(i) = (mod(a * x(i-1)+c ,m))
end
here i want to skip the first value x(1)=2 to print in each iteration.
so please guide me how can i skip this value in output. 

Answer 1

[David Hill]

a = 27;
c = 11;
m = 54;
x(1)=2;
for i=2:25
    x(i) = (mod(a * x(i-1)+c ,m))
end
x(2:end)

[Kapil Gupta]

a = 27;
c = 11;
m = 54;
for i=2:25
    x(1)=2;
    x(i) = (mod(a * x(i-1)+c ,m))
    R(i) = x(i)/m;
    if x(i) == x(1)
        fprintf('%.2f\n',i-1)
        break
    end
end
x(2:end)

this is problem i ihave an another condition but it not fulfil by your code.

[Kapil Gupta]

i want to skip the x=2 in each iteration.

and from my code i received output after each iteration that is too long.so i need a single array output please suggest me.

[David Hill]

I don't understand what you are saying. Please explain more. What do you want your output to be?

[Kapil Gupta]

i want to skip first element from each output after each iteration.and follow the loop with if condition and print a single output for x(i) and R(i).now i think you may understand my problem.

[David Hill]

Show me what you want for your output (i=2:4)

Answer 2

[dpb]

AMENDED:

Probably simplest is just

a = 27;
c = 11;
m = 54;
x(1)=2;
for i=2:25
  x(i) = (mod(a * x(i-1)+c ,m));
end
x=x(2:end);

maybe? Just guessing; we can't tell what it is that you really want, unfortunately.

[Kapil Gupta]

In your answer if condition is not fulfil.

[dpb]

What "if" is that??? No if's and's or but's in the question...just the wish to not display the "2" at the begining of each x vector.

The only If is that if we can't understand the question/desired output clearly we can't solve the problem.

Show explicitly what the specific output expected should be.