How to draw normal line at given points ?

조회 수: 27 (최근 30일)
MMSAAH
MMSAAH 2020년 3월 27일
답변: michael scheinfeild 2021년 8월 28일
Hello everyone,
I have a red curve that fit 4 bleu points. I want to draw normal at these points.
Here attached my curve.
and the x, y coordinates of the bleu points are :
x=[142;127;181;234];
y=[251;251;261;255];
So, please, how to get the normal line ?
I will be very grateful if anyone could help me.
  댓글 수: 2
Ameer Hamza
Ameer Hamza 2020년 3월 27일
How did you create this curved line fitting through these points?
MMSAAH
MMSAAH 2020년 3월 30일
Hello Ameer,
Here is my code:
x=[142;127;181;234]
y=[251;251;261;255]
p = polyfit(x, y, 1);
v = polyval(p, x);
xint = linspace(127,300,50)';
spl = spline(x,y);
figure
t=plot(y,x,'.',ppval(spl,xint),xint,'r-')
xlim([200 300])
ylim([50 234])

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채택된 답변

Ameer Hamza
Ameer Hamza 2020년 3월 31일
Try this:
x=[142;127;181;234];
y=[251;251;261;255];
[x, idx] = sort(x);
y = y(idx);
points = [x y];
xint = linspace(127,234,50)';
spl = spline(x,y);
tangent_vector = zeros(4,2);
for i=1:4
if i==4 % last polynomial need to evalauted at endpoint
deri_coef = polyder(spl.coefs(i-1,:));
tangent_vector(i, :) = [1 polyval(deri_coef, x(end)-x(end-1))];
else
deri_coef = polyder(spl.coefs(i,:));
tangent_vector(i, :) = [1 polyval(deri_coef, 0)];
end
end
normal_vec = [-tangent_vector(:,2) tangent_vector(:,1)];
start_points = points;
end_points = 10*normal_vec + points;
fig = figure;
ax = axes();
hold(ax);
t = plot(y,x,'.',ppval(spl,xint),xint,'r-');
for i=1:4
p1 = start_points(i,:);
p2 = end_points(i,:);
plot([p1(2) p2(2)], [p1(1) p2(1)], 'r', 'LineWidth', 2);
end
daspect([1 1 1]);
xlim([180 340])
ylim([100 250])
  댓글 수: 2
MMSAAH
MMSAAH 2020년 4월 1일
Thank you very much for the answer.It worked perfectly.
However, could you explain me more the for loop ? and why did you evaluated the polynome at endpoint ?
Thank you though!
Ameer Hamza
Ameer Hamza 2020년 4월 1일
For loop is just calculating the tangent vector at each point, since we can calculate the normal vectors from tangent vectors. The spline function output 3 polynomials for 4 data points. So to compute tangent at 4 data points, we need to do it like this
datapoint # 1 -> polynomial # 1 (start point)
datapoint # 2 -> polynomial # 2 (start point) or polynomial # 1 (end point)
datapoint # 3 -> polynomial # 3 (start point) or polynomial # 2 (end point)
datapoint # 4 -> polynomial # 3 (end point)
Which shows where I evaluated the derivative of each polynomial

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추가 답변 (1개)

michael scheinfeild
michael scheinfeild 2021년 8월 28일
https://michaelsheinfeild.medium.com/unit-normal-vector-to-curve-d63ef0124acd

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