Is there a function in MATLAB that generates the following matrix for a given scalar r, where each row behaves somewhat like a power analog of the CUMSUM function?:
1 r r^2 r^3 ... r^n
0 1 r r^2 ... r^(n-1)
0 0 1 r ... r^(n-2)
...
0 0 0 0 ... 1

댓글 수: 1

Rik
Rik 2020년 3월 24일
I doubt there is a direct function. Have you tried writing one yourself?

댓글을 달려면 로그인하십시오.

 채택된 답변

Birdman
Birdman 2020년 3월 24일

2 개 추천

Try the following code. By changing r and n values, you can see the corresponding results.
r=9;n=4;
A=zeros(n+1,n+1);
for i=1:size(A,1)
for j=1:size(A,2)
if (j-i)<0
A(i,j)=0;
else
A(i,j)=r^(j-i);
end
end
end
A

추가 답변 (1개)

Rik
Rik 2020년 3월 24일
편집: Rik 2020년 3월 24일

1 개 추천

This code does what you ask without loops.
%define inputs
r=9;
n=4;
[a,b]=meshgrid(0:n);
exponents=a-b;
exponents(exponents<0)=NaN;
result=r.^exponents;
result(isnan(result))=0;

댓글 수: 5

Birdman
Birdman 2020년 3월 24일
This code is slower than mine although you avoided nested for loops.
Strange. I did a tic,toc to check and mine was about twice as fast, but with the code below yours is 10 times faster. It probably also depends on n and r.
r=9;n=4;
timeit(@() option_loop(r,n))
timeit(@() option_grid(r,n))
function A=option_loop(r,n)
A=zeros(n+1,n+1);
for i=1:size(A,1)
for j=1:size(A,2)
if (j-i)<0
A(i,j)=0;
else
A(i,j)=r^(j-i);
end
end
end
end
function result=option_grid(r,n)
[a,b]=meshgrid(0:n);
exponents=a-b;
exponents(exponents<0)=NaN;
result=r.^exponents;
result(isnan(result))=0;
end
Birdman
Birdman 2020년 3월 24일
Your answer is neat but my point is there is no reason to avoid nested for loops because there is no dramatic time consumption.
This is actually a nice illustration of the fact that a non-loop version isn't always faster. In this case (at least on my computer with Windows 10 and R2019a) the looped version is faster up to about n=30. For huge values of n there may very well be a tangible benefit (or if this code is going to be run very often).
clc,clear
r=9;
n_list=[1:100 200:100:1000];
t=zeros(2,numel(n_list));
for it=1:size(t,2)
n=n_list(it);
t(1,it)=timeit(@() option_loop(r,n));
t(2,it)=timeit(@() option_grid(r,n));
end
figure(1),clf(1)
plot(n_list,t(1,:),n_list,t(2,:))
legend({'loop','grid'})
xlabel('n'),ylabel('time')
Herr K
Herr K 2020년 3월 24일
Thanks for your answer. Now I learn the meshgrid function as well!

댓글을 달려면 로그인하십시오.

카테고리

도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

태그

질문:

2020년 3월 24일

댓글:

2020년 3월 24일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by