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combining 3 for loops

조회 수: 3 (최근 30일)
Nur Amalina
Nur Amalina 2020년 3월 16일
댓글: Sriram Tadavarty 2020년 3월 17일
Hi, All!
I have 3 "for" loops but i confuse when combining one and another. I need vector u, depend on x(j)-x(i) and x(i,t)-x(i,t-1)
this is the best function i've tried before. So glad to know that anyone can correct and help me :)
for t=1:1000
for i=1:5
for j=1:5
u(i,j)= a1*adj2(i,j)*(x(j)- x(i))+a2*(x(i,t)-x(i,t-1));
end
end
u=sum(u,2)
end
  댓글 수: 3
Bob Thompson
Bob Thompson 2020년 3월 16일
Also, what exactly is the problem you're experiencing? Are you getting an error message, or are you just not getting the output you would expect. If the output is different, what does it look like, and how were you expecting it to be different?
To add to tmarske's point about the different forms of indexing, if x is a 2D array then x(j) - x(i) will return a reduced vector, while x(i,t) - x(i,t-1) will return a single element. This is not inherently a problem, depending on the size of a1, adj2, and a2, but MATLAB will not let you perform a '+' operation on two components of different sizes like that.
Nur Amalina
Nur Amalina 2020년 3월 17일
First, thanks for the reply. a1 and a2 are only a constant value while u and x are 2D array. row by n. column by t. in this case it will be 5x1000. adj2 is 5x5 matrix.
I am getting an error message "Index in position 2 exceeds array bounds (must not exceed 1)." hmm maybe the problem like Bob said. "x(j) - x(i) will return a reduced vector, while x(i,t) - x(i,t-1) will return a single element" any advice what should i do to make it be the same size?

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Sriram Tadavarty
Sriram Tadavarty 2020년 3월 17일
편집: Sriram Tadavarty 2020년 3월 17일
Hi Nur,
If the code is updated to run from time t set from 2 to 1000, this should go away with the error you see.
The subtraction of x(j) and x(i) would only do it for the first five elements all the time. I think this is not the intention. It should be x(j,t) and x(i,t)
With these changes the code looks as such:
for t=2:1000
for i=1:5
for j=1:5
u(i,j,t)= a1*adj2(i,j)*(x(j,t)- x(i,t))+a2*(x(i,t)-x(i,t-1));
end
end
u=sum(u,2)
end
u = permute(u,[1 3 2]);
Hope this helps.
Regards,
Sriram
  댓글 수: 6
Nur Amalina
Nur Amalina 2020년 3월 17일
problem solve Sriram. Thank you very much!
Sriram Tadavarty
Sriram Tadavarty 2020년 3월 17일
That's nice to hear Nur. Do accept the answer if it helped.

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