Vectorization, avoiding loops

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Jarl Bergström
Jarl Bergström 2020년 3월 11일
댓글: Jarl Bergström 2020년 3월 14일
Hello!
I have a Matrix, A=rand(9,10)
Now, I want to add a new number, to a new row, for every column b=[2,3,4;7 1 6];
I can do this using loops but I want to use Vectorization for speed.
A ( end +1 , b(1) ) = 1
A ( end +1 , b(2) ) = 1
A ( end +1 , b(3) ) = 1
Thank you :)

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tmarske
tmarske 2020년 3월 11일
Assuming this:
b=[2,3,4;7 1 6];
is a typo and supposed to read:
b=[2,3,4,7,1,6];
Then you can make the new rows as a matrix of zeros, set appropriate elements = 1, then concatenate:
A = rand(9, 10)
b=[2,3,4,7,1,6];
%make the new rows as a single block
newRows = zeros(length(b), size(A, 2));
bIx = sub2ind(size(newRows), 1:length(b), b);
newRows(bIx) = 1;
%concatenate them
A = [A; newRows]
Example output:
A =
0.5470 0.0811 0.8176 0.5502 0.2259 0.9797 0.2217 0.0292 0.5211 0.8852
0.2963 0.9294 0.7948 0.6225 0.1707 0.4389 0.1174 0.9289 0.2316 0.9133
0.7447 0.7757 0.6443 0.5870 0.2277 0.1111 0.2967 0.7303 0.4889 0.7962
0.1890 0.4868 0.3786 0.2077 0.4357 0.2581 0.3188 0.4886 0.6241 0.0987
0.6868 0.4359 0.8116 0.3012 0.3111 0.4087 0.4242 0.5785 0.6791 0.2619
0.1835 0.4468 0.5328 0.4709 0.9234 0.5949 0.5079 0.2373 0.3955 0.3354
0.3685 0.3063 0.3507 0.2305 0.4302 0.2622 0.0855 0.4588 0.3674 0.6797
0.6256 0.5085 0.9390 0.8443 0.1848 0.6028 0.2625 0.9631 0.9880 0.1366
0.7802 0.5108 0.8759 0.1948 0.9049 0.7112 0.8010 0.5468 0.0377 0.7212
A =
0.5470 0.0811 0.8176 0.5502 0.2259 0.9797 0.2217 0.0292 0.5211 0.8852
0.2963 0.9294 0.7948 0.6225 0.1707 0.4389 0.1174 0.9289 0.2316 0.9133
0.7447 0.7757 0.6443 0.5870 0.2277 0.1111 0.2967 0.7303 0.4889 0.7962
0.1890 0.4868 0.3786 0.2077 0.4357 0.2581 0.3188 0.4886 0.6241 0.0987
0.6868 0.4359 0.8116 0.3012 0.3111 0.4087 0.4242 0.5785 0.6791 0.2619
0.1835 0.4468 0.5328 0.4709 0.9234 0.5949 0.5079 0.2373 0.3955 0.3354
0.3685 0.3063 0.3507 0.2305 0.4302 0.2622 0.0855 0.4588 0.3674 0.6797
0.6256 0.5085 0.9390 0.8443 0.1848 0.6028 0.2625 0.9631 0.9880 0.1366
0.7802 0.5108 0.8759 0.1948 0.9049 0.7112 0.8010 0.5468 0.0377 0.7212
0 1.0000 0 0 0 0 0 0 0 0
0 0 1.0000 0 0 0 0 0 0 0
0 0 0 1.0000 0 0 0 0 0 0
0 0 0 0 0 0 1.0000 0 0 0
1.0000 0 0 0 0 0 0 0 0 0
0 0 0 0 0 1.0000 0 0 0 0
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Jarl Bergström
Jarl Bergström 2020년 3월 14일
Thank you very much!!

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