What’s my error ?!

[Adam Danz]

This is better than the 1-line of code you had previously but an image of code makes it difficult for us to work with since we can't copy-paste it.

Since I already copyied your previous line of code, here's what it should look like when formatted properly.

i=1;
x(i)=5;
error(i)=9999;
while error (i) >=(0.5)
    X(i+1)=((x(i)^2-2.5)/(1.8));
    error(i+1)=abs((((x(i+1)-x(i))/(x(i+1)))*1000));
    i=i+1;
end

To use smart-indentation, highlight all of your code (ctrl+A, in Window, followed by ctrl+i).

Answer 1

[Adam Danz]

One reason it's difficult to see the error is because all of your code is in 1 line. There's no advantage to doing this. Disadvantages are

• Really diffcult to read
• Error messages aren't helpful in pointing to the error
• It's realy difficult to see what parts of the code are in loops, etc

Your code contains a variable X (upper case) which should probably be x (lower case).

Also, don't use error as a variable name since error() is a common function.

You should also replace the while-loop with a for-loop if i is an interger starting with 1 that increases incrementally.

[Walter Roberson]

There are an unknown number of iterations, so you cannot use a for loop.

[Adam Danz]

When I run the code, after replaceing X with x, on the 10th iteration x equals inf and error equals NaN which ends the while-condition. It stops after 10 iterations (when i equals 11).