Read and write csv files without changing properties
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I've succesfully solved a big problem thanks to you guys and now I'm facing a slightly smaller but important one.
(Following code is the original one posted by another mvp here. Kudos)
data = int64(csvread('Sample_02.csv'));
time = data(:,2);
% remove empty rows
data = data(time>0, :);
time = time(time>0);
time = mod(time, 1000000); % yyyymmdd are not important so discard them
current_time = 00000; % time in hhmmss format
while size(data, 1) > 0
next_time = current_time + 30000; % 30000 represent 3 hours
index = time < (current_time + 30000);
partial_data = data(index, :);
dlmwrite(['data-' num2str(current_time/10000) '-' num2str(next_time/10000) '.csv'], ...
partial_data, 'precision', '%i');
data(index,:) = [];
time(index,:) = [];
current_time = current_time + 30000;
end
The code reads the sample CSV file and split it in to seperate csv files based on time-stamps.
My problem is: The original csv file (Sample_02.csv) has 7 columns and the above code only deals with the second one. Output files also have 7 columns, obviously, but the values are not shown/stored as decimals. For example, the original CSV file stores 123.456789 in its 6th column but the generated output files have only 123 in the respective 6th column.
How can I store the same data as decimals in the output files?
TIA!
댓글 수: 6
Walter Roberson
2020년 3월 10일
Don't use 'precision', '%i' -- the %i means to only write out integers.
Preserving the same number of decimal places as the original requires processing the lines as text rather than numeric.
Jake
2020년 3월 10일
Walter Roberson
2020년 3월 10일
Preserving the same number of decimal places as the original requires processing the lines as text rather than numeric.
Jake
2020년 3월 10일
Mohammad Sami
2020년 3월 10일
I tested your sample file with readtable and writetable. It seems to work as you desire. I am using R2019b.
Jake
2020년 3월 11일
채택된 답변
추가 답변 (1개)
Walter Roberson
2020년 3월 10일
0 개 추천
fileread to read the file into a string.
textscan the string to extract the datetime as numeric.
Now regexp the string with '\r?\n', 'split' to create a cell array in which each entry is a line.
Use the information in the numeric date to figure out where to split. The indices can be used in the cell array of split lines. strjoin() those cells with '\n' and fwrite() the result.
댓글 수: 3
Jake
2020년 3월 11일
Walter Roberson
2020년 3월 11일
S = fileread(filename);
fmt = '%*f,%ld,%*s';
C2 = cell2mat(textscan(S, fmt));
lines = regexp(S, '\r?\n', 'split');
time = double(mod(C2, 1e6));
...
mask = start_time <= time & time < end_time;
subset = strjoin(lines(mask), '\n') ;
fwrite(fid, subset);
Jake
2020년 3월 11일
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