How to integrate a signal sawtooth?

I'm integrrating the signal sawtooth using the function "integral" such that "0" min limit and "i" is the max limit to get values of theta to plot it with time but there is an error 'Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters.'

Can you help please ?

fs = 1000;
kf=1000;
t = 0:1/fs:2;
signal = @(tt) sawtooth(pi*2*tt+pi);
theta=[];
for i = (0:1/fs:2)
theta=2*pi*kf*integral(signal,0,i);
end
plot(t,theta[i])

Answer 1

[Star Strider]

Try this:

fs = 1000;
kf=1000;
t = 0:1/fs:2;
signal = @(tt) sawtooth(pi*2*tt+pi);
theta=zeros(size(t));
for i = 1:numel(t)
    theta(i)=integral(signal,0,t(i));
end

figure
plot(t,theta)

It is necessary here to subscript ‘t’ and ‘theta’ in the loop to create the desired vectors.

[moustafa abada]

Thanks a lot. It workd!

[Star Strider]

As always, my pleasure!