Finding a specific row in a matrix based on user inputs?

조회 수: 5 (최근 30일)
Nicholas DeGarmo
Nicholas DeGarmo 2020년 2월 26일
댓글: KALYAN ACHARJYA 2020년 2월 27일
I have a matrix with 365 rows and 7 columns, the first column is the month (1-12) and the second column is a day of that month. The user inputs what month they want to look at in a numeric value (1-12) and then the day they want (1-31), but then I need to take that input data and only find the array with those two specific values, I have no clue how to copy just that row based on those two inputs.
Images to explain:

답변 (2개)

KALYAN ACHARJYA
KALYAN ACHARJYA 2020년 2월 27일
편집: KALYAN ACHARJYA 2020년 2월 27일
#Do the necessary changes, as required
%let say mat_data is the main matrix
mat_data=[1 1 3 4 56
1 2 3 4 50
1 3 4 5 90
2 3 5 6 70];
month=input('Enter the Month Any value 1-12: ');
day=input('Enter the Day Any value 1-31: ');
disp('The details is ');
mat_data(mat_data(:,1)==month & mat_data(:,2)==day,:)
  댓글 수: 2
KSSV
KSSV 2020년 2월 27일
Why to use find when we have logical indexing at best?
KALYAN ACHARJYA
KALYAN ACHARJYA 2020년 2월 27일
Yes, thanks for pointing it out

댓글을 달려면 로그인하십시오.


KSSV
KSSV 2020년 2월 27일
편집: KSSV 2020년 2월 27일
Let A be your matrix of size 365*7.
themonths = A(:,1) ;
thedays = A(:,2) ;
% Let us say I want 7th month and 7th day indices
m = 7 ; d = 7 ;
idx = themonths == m && thedays == d ;
iwant = A(idx,:) ;

카테고리

Help CenterFile Exchange에서 Multidimensional Arrays에 대해 자세히 알아보기

제품


릴리스

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by