How to guess initialization parameters for non-linear curve fitting with nlinfit?
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I'm trying to use fit the data using this equation:
gaussFit = @(beta, stepFit) (beta(1).*(( ((stepFit./beta(2)).^4)/(1+((stepFit./beta(2)).^4))).*exp((-1).*(stepFit./beta(3))).*cos( (((2*pi).*stepFit)./beta(4)) + beta(5))));
initials = [-0.000006, 0.07, 0.06, 0.12, 0.15];
coeffs = lsqcurvefit(gaussFit, initials, stepFit, avgSPResp2);
(Data attached)
But it is giving me a staight line (which I'm guessing is because the initials are way off compared to the actual fit parameters. However, I've tried to estimate the parameters as much as possible looking at the data.
How do I address this issue?
Thanks!
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Alex Sha
2020년 2월 27일
Hi, Aindrila, guessing the initial start value is always a difficult task since the local optimization algorithms are adopted in most of curve fitting tool or commond,i.e. lsqcurvefit, “Luck + experience” is the current approach, or other way you may try is to use some packages which can performance global optimization calculation,refer the result below:
Root of Mean Square Error (RMSE): 0.0688616729634862
Sum of Squared Residual: 8.77731243616407
Correlation Coef. (R): 0.993270819763553
R-Square: 0.98658692139376
Adjusted R-Square: 0.986572405074922
Determination Coef. (DC): 0.9865195863016
Chi-Square: -3.03449530351813
F-Statistic: 34240.770055333
Parameter Best Estimate
---------- -------------
beta1 308.324915419002
beta2 -0.233165245624372
beta3 0.0481053716827587
beta4 0.351440892233252
beta5 -0.634236150207208
추가 답변 (1개)
Matt J
2020년 2월 28일
편집: Matt J
2020년 2월 28일
Maybe by doing a Gaussian fit first, it would be easier to guess what the beta(i) parameters should be. You can do a Gaussian fit using gaussfitn (Download).
params=gaussfitn(stepFit,avgSPResp2);
[D,A,mu,sig]=deal(params{:})
z=@(x) D + A*exp( -0.5 * (x-mu).' * inv(sig) *(x-mu) );
hold on
xlims=[min(stepFit),max(stepFit)];
plot(stepFit,avgSPResp2,'ro')
fplot(z,xlims,'Color','k')
xlabel 'stepFit'
ylabel 'avgSPRResp2'
hold off
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