필터 지우기
필터 지우기

Avoid nans in 2D cubic spline interpolation

조회 수: 10 (최근 30일)
icylab
icylab 2020년 2월 24일
댓글: darova 2020년 3월 2일
I have XYZ data (X and Y are the coordinates of Z values). Intermintently, the Z values have NaNs.The data is a radar line with gaps in the data (hence the NaNs) and uneven spacing between each points (see figure, blue is the existing values, orange is the NaN values). What I would like is to interpolate the non-nan values on a regular spacing and leave the nans as they are. My XYZ array is +40k rows and contains approximately +5k of NaNs, sometimes consecutive and sometimes spread out.
I am using the interparc function from John (https://uk.mathworks.com/matlabcentral/fileexchange/34874-interparc) to interpolate my points as I am working with a curved line and do not want to create a meshgrid, but I get an error message every time:
Warning: All data points with NaN as their site will be ignored.
> In chckxy (line 37)
In spline (line 53)
In interparc (line 316)
Error using chckxy (line 42)
There should be at least two data points.
I have tried to replace the NaNs by an arbitrary value (999) and make each value unique, as per (https://uk.mathworks.com/matlabcentral/answers/344604-how-to-change-duplicate-values-so-that-every-value-is-unique)
% replace nans by value
new2_dpth(isnan(new2_dpth)) = 999;
% create unique values for NaNs
a = new2_dpth;
[uvals, ~, uidx] = unique(a, 'stable');
b = a;
for K = 1 : length(uvals)
mask = uidx == K;
b(mask) = uvals(K) + (0 : nnz(mask) - 1) * 0.01;
end
I can then interpolate this and remove any value above a certain threshold, but get very strange results (see second figure).
I have also tried to remove the nan's from the interpolation using a for and if loop, but this is time consuming and does not seem to work either (see below)
f=[];
for i = 1:length(b)
if b (i) ~= -999
f = interparc (100,new2_x,new2_y,b);
else
continue
end
end
Any help would be really appreciated! Thanks.
  댓글 수: 2
darova
darova 2020년 2월 24일
Is this correct?
icylab
icylab 2020년 2월 25일
Hi Darova,
Thanks for your help. Yes I guess this is similar to what I need. However, I already know how to interpolate data on a regular grid. I just need this interpolation to stop before and start after the nans (and not interpolate them). I'm not sure your figure does that?

댓글을 달려면 로그인하십시오.

답변 (1개)

darova
darova 2020년 2월 26일
Here is what i tried: Created new mesh and place there NaN (red points_
clc,clear
% generate random data
x = sort(rand(1,20)*5);
y = sin(x);
z = x.^2;
ix = [2 7 12 18]; % indices of NaN's
plot3(x,y,z,'.-b')
hold on
plot3(x(ix),y(ix),z(ix),'ok')
hold off
t = [0 cumsum(sqrt(diff(x).^2+diff(y).^2+diff(z).^2))];
ti = linspace(0,t(end),15); % new mesh
[tt,in] = sort([t(ix) ti]); % sort new mesh and NaN points
[~,ii] = sort(in); % sort indices to get places of NaN
% interpolate data with mesh
xx = spline(t,x,tt);
yy = spline(t,y,tt);
zz = spline(t,z,tt);
i1 = ii(1:length(ix)); % first indices are NaN
hold on
plot3(xx,yy,zz+3,'.:r')
plot3(xx(i1),yy(i1),zz(i1)+3,'ok')
zz(i1) = nan; % place NaN in data to create breaks
plot3(xx,yy,zz+3,'-r','linewidth',2)
hold off
axis vis3d
  댓글 수: 6
icylab
icylab 2020년 3월 2일
Only in new2dd
darova
darova 2020년 3월 2일
Try this
zz = spline(t(~ix),new2_dd(~ix),tt); % take only number (without NaN)
I gave you incorrect example above
t = [0 cumsum(sqrt(diff(x).^2+diff(y).^2+diff(z).^2))];
Because z in your case have NaN's. You can't use it

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Surface and Mesh Plots에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by