Generate a 32-bit binary stream

I am trying to genrate a binary stream using this function and have searched a lot but came out emty.

The main problem I am facing is mainly the binary addition on every addition and the size of the increasing stream.

The Equation is below:

I tried to use the rand fucntion but it isnt right. I realised the Binary addition was not happening.

The final result should be a float number within [0,1).

pold = [];
pf=0;
for i=1:32
    param = round(rand(1,1));
    pf = param + pf;
    pold(i) = pf*2^(-i);
    pold(i);
end

Answer 1

[Walter Roberson]

sum(randi([0,1],1,32).*2.^-(0:31))

Or

randi([0,2^32-1])/2^32

Or you can use rnd() or related to tell rand to use the shr3cong generator, which has the required results.

Or you could rand() and throw away bits 33 to 52.

[Steve Rogerson]

Thank you kind Sir!