Matrix index is out of range for deletion and I cant figure it out

I am getting the error "Matrix index is out of range for deletion". What I am trying to accomplish is: where ever there is a 0 in f.....i want to delete that row number from g.

g =

1 1 1 1

2 2 2 2

3 3 3 3

4 4 4 4

5 5 5 5

f =

1 1 0 1 0

>> for j= 1:numel(f)

if f(j)==0

g(j,:)=[]

end

end

g =

1 1 1 1

2 2 2 2

4 4 4 4

5 5 5 5

Matrix index is out of range for deletion.

The output should be g without the 3rd and 5th row.

g=[1 1 1 1; 2 2 2 2; 4 4 4 4]

Answer 1

[Walter Roberson]

Suppose you delete row 4. What was in row 5 "falls down" to row 4,what was in 6 falls to 5, and so on. If you had a request to delete row 6 then in order to delete it now, you would have to delete what is now row 5, because 6 fell to 5.

It is possible to work with a running total of the number you have deleted to figure out the current index of a given row.

However it is far easier to simply loop backwards. Delete from highest row number first: anything that falls down will be something you already know should not be deleted.

Or you could just vectorize the entire loop:

g(f==0,:) = [] ;

[Nikolas Vieira]

Makes perfect sense, thanks