Calculating the sum of each row in a matrix.

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Serra Aksoy
Serra Aksoy 2020년 2월 7일
편집: Guillaume 2020년 2월 12일
Hi,
I have a code like this:
X = [1 2 3 4 5;
3 5 7 9 11;
2 4 6 8 10;
3 9 12 15 18];
minx = min(X, [ ], 2); %min of each vector
maxx = max(X, [ ], 2); %max of each vector
result = X >= reshape(minx, 1, 1, [ ]) & X <= reshape(maxx, 1, 1, [])
When i run it,
result is 4x5x4 logical and
val(:,:,1) =
1 1 1 1 1
1 1 0 0 0
1 1 0 0 0
1 0 0 0 0
Here i have a question.
I would like to see the sum of each row with names.
In val(:,:,1), the sum of first row= A11, sum of second row= A12, sum of third row= A13 and sum of fourth row=A14 .
Likewise for
val(:,:,2) =
0 0 1 1 1
1 1 1 1 1
0 1 1 1 1
1 1 0 0 0
sum of first row= A21, sum of second row= A22,...
I tried to do this with creating a 4X4 matrix A which consist of the sum values A11, A12, A13 A14, .... But i cant do it.
Any help is appreciated.
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Adam Danz
Adam Danz 2020년 2월 8일
Note #2: this quesiton may have migrated to a new question.

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답변(1개)

Sourav Bairagya
Sourav Bairagya 2020년 2월 12일
You can use 'sum' function to compute sum for each row and then can apply 'squueze' function to remove the singleton dimension (i.e. dimension with length 1). After that you can take transpose of the result and you will get the desired output.
val = sum(result,2);
out = squeeze(val);
A = out';
You can leverage these links for further information:
  댓글 수: 1
Guillaume
Guillaume 2020년 2월 12일
Or you can do the squeeze and transpose altogether with just one permute:
A = permute(sum(result, 2) [2 3 1]) %note this do a .' transpose instead of a ' ctranspose. For a logical array the two are the same.

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