Hi there,
I have a 3D array (mask) with the numbers 0 background, 1, 2, 3 and 4. The numbers 1,2,3 and 4 correspond to particular regions.
I want to count how many regions in my 3D mask have the number 1,2,3, or 4.
Does anyone know how to do this?

 채택된 답변

Rik
Rik 2020년 2월 6일
편집: Rik 2020년 2월 7일
You can use bwlabeln to label all your non-zero regions. then you can loop through each of the labeled regions to determine which number they have. With that, you essentially have the result you need.
If you don't have the image processing toolbox, let me know, because I have an alternative that doesn't require any toolbox.
Edit: added the example below.
%generate example data where max(L(:)) returns about 30
IM=randi(300000,100,100,100);
IM(IM>10)=0;
[L,n_regions]=bwlabeln(IM>0);
counts=zeros(1,max(IM(:)));
for n=1:n_regions
ind=find(L==n,1);
field_val=IM(ind);
counts(field_val)=counts(field_val)+1;
end

댓글 수: 4

Hi Rik,
Thanks for your reply. I tried the bwlabeln function like this:
[L,n] = bwlabeln(mask);
When I printed n, I got the number 32. This is actually the correct number of regions I have (non-zero) but it doesn't give me how many regions of these 32 have number 1, how many number 2, how many number 3 etc.
How can I do that?
Rik
Rik 2020년 2월 7일
I added an example to my answer. Let me know if there is anything unclear.
I think I see how it works. When I print the counts I got the following:
counts =
4 5 4 2 2 4 1 5 1 5
That means I have 4 regions with number 1, 5 regions with number 2 etc. Am I correct?
Rik
Rik 2020년 2월 8일
Yes, that is the idea. There might be more efficient ways to get to this vector, but this is what I could come up with.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

질문:

2020년 2월 6일

댓글:

Rik
2020년 2월 8일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by