How to simplify the loops of a matrix
조회 수: 1 (최근 30일)
이전 댓글 표시
Hello. I have an issue with a code performing some calculations in two loops . It is very slow since I am using two loops. Could you please help me solve this,
Clear all
nx = 100;
ny = 200;
phi = random(nx,ny);
num = 5;
phi1 =zeros(nx,ny);
for i =1:nx
for j = 1:ny
phi1 = mod(phi(i,j), num);
end
end
figure(1)
surf(phi1)
댓글 수: 0
채택된 답변
Robert U
2020년 2월 6일
Hi Xinyuan,
the code snippet you are providing does not make any use of the two for-loops. You can remove them, since the function mod() is applied to each element of the matrix "phi". The result is the same. Your code just overwrites the same matrix for nx x ny times.
clear all
nx = 100;
ny = 200;
phi = rand(nx,ny);
num = 5;
phi1 = mod(phi, num);
figure
surf(phi1)
Kind regards,
Robert
댓글 수: 4
Robert U
2020년 2월 6일
Hi Xinyuan,
your introduced change illustrates the problem that you solved partially yourself posting the former code snippet:
Remove the two for-loops and the indexing. The function mod() performs the modulo-operator on each single element of the matrix phi, thus there is no loop necessary.
Kind regards,
Robert
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!