Replace multiple matrix in a cell array based on condition
조회 수: 2 (최근 30일)
이전 댓글 표시
need a help in replacing matrix in cell array
if i have cell array and matrix like this
A = {[1,1,2; 2,2,3];[1,3,4; 9,6,8];[1,7,8; 2,3,4];[1,1,4; 8,6,5]};
B = [2,2,2; 3,3,3];
when A has a value more than 5, it should be replace with B
then, the result have to be like this
result = {[1,1,2; 2,2,3];[2,2,2; 3,3,3];[2,2,2; 3,3,3];[2,2,2; 3,3,3]};
i have tried this, but it still gives me an error
rep = cellfun(@(c) any(any(c>5)), A, 'UniformOutput', true);
A{rep} = B;
Expected one output from a curly brace or dot indexing expression, but there were 2 results.
Any idea ?
Thanks in advance..
댓글 수: 0
채택된 답변
Stephen23
2020년 2월 5일
편집: Stephen23
2020년 2월 5일
You were almost there, just one small change is required:
To assign to an unknown number of LHS elements the RHS must be scalar. In your case you want to assign cells themselves so the simplest is to make the RHS one scalar cell (not a non-scalar numeric).
>> idx = cellfun(@(c) any(c(:)>5), A); % default UniformOutput = True
>> A(idx) = {B}; % unknown number of cells = scalar cell
>> A{:}
ans =
1 1 2
2 2 3
ans =
2 2 2
3 3 3
ans =
2 2 2
3 3 3
ans =
2 2 2
3 3 3
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Matrix Indexing에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!