summing elements of an array until a value appears
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I'm trying to execute a for loop that looks at permutations of a set and sums all the elements until a specific element 'k' is reached.
rather than sum(line(1:k)) i need effectively sum(line(1:'k')) but inputting that exactly doesn't work. Any ideas?
if sum(line(1:k))>=q && (sum(line(1:k))-k)<q
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Turlough Hughes
2020년 1월 29일
I don't get what you mean by sum(line(1:'k')) vs sum(line(1:k)), can you clarify?
Turlough Hughes
2020년 1월 29일
Thomas Gvero
2020년 1월 29일
Thomas Gvero
2020년 1월 29일
채택된 답변
추가 답변 (2개)
the cyclist
2020년 1월 29일
Here is one way.
% Inputs
inputVector = [5 4 3 2 1];
inputValueToFind = 2;
% Find the location of the index
idxEnd = find(inputVector==inputValueToFind,1);
% Sum up to that index
sum(inputVector(1:idxEnd))
Turlough Hughes
2020년 1월 29일
편집: Turlough Hughes
2020년 1월 29일
Say your array is called data:
q=2;
data = [1 2 3; 1 3 2; 2 1 3; 1 0 3; 1 2 2]; % Includes rows without any values = q, and repeated q.
You could then get the cumulative sum of values up to the first occurence of q in each row as follows:
[ ~,k ] = max(data == q,[],2); % Index for first column equal to q in each row.
k(~any(data == q,2)) = 0 % Case for rows that have no values == q.
for c = 1:numel(k)
csums(c,1) = sum( data(c,1:k(c)) );
end
Here, data == q is a logical array of all values in data that are equal to q. Taking the max along each row will return the "first" index for a given row in data being equal to q. The second line accounts for cases where no values are equal to q.
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