Why not adding space between words
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이전 댓글 표시
strcat('Scale Factor = ',num2str(table2array(T(min(find(find_groups==k)),'scalefactor'))))
and the output is like:
'Scale Factor =0.65'
I need to add the space between = and 0.65. Using above code does not add the space. Any idea/solution?
댓글 수: 1
Guillaume
2020년 1월 29일
Please note in Walter's answer how he simplified the horror that is:
table2array(T(min(find(find_groups==k)),'scalefactor')))
to
T.scalefactor(find(find_groups==k,1)))
Use proper table indexing,
table2array(Atable(rows, 'variablename')) %() indexing on a table returns a table
is simply
Atable.variablename(rows) %. indexing returns the content of the table
%or
Atable{rows, 'variablename'} % {} indexing returns the content of the table
and
min(find(something))
is simply
find(something, 1) %get the first element only
채택된 답변
Image Analyst
2020년 1월 29일
Try fprintf()
theNumber = table2array(T(min(find(find_groups==k)),'scalefactor')); % Whatever...but don't use num2str()
fprintf('Scale Factor = %.2f.\n', theNumber);
댓글 수: 6
Guillaume
2020년 1월 29일
If you don't put any restriction on the format length, then matlab won't truncate the input. So
sprintf('Name = %s', theName) %no limit to 2 characters
would work.
If you want a minimum field width of 2 characters but more if required, then
sprintf('Name = %2s', theName) %No . in the format string. Minimum field width of 2, padding with spaces if required
추가 답변 (2개)
Walter Roberson
2020년 1월 29일
For character array inputs, strcat removes trailing ASCII white-space characters: space, tab, vertical tab, newline, carriage return, and form feed. For cell and string array inputs, strcat does not remove trailing white space.
댓글 수: 2
Walter Roberson
2020년 1월 29일
strcat({'Scale Factor = '}, num2str(T.scalefactor(find(find_groups==k,1))))
Steven Lord
2020년 1월 29일
If you're using a release that supports string arrays, you can simplify this a bit if you trust MATLAB to do "something reasonable" when combining your text and numeric data.
x = 0.65;
S = "Name = " + x
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