Better parallelization than parfor?
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Hello,
I have a function fun(vec(1:n),Nmax) with two outputs: (i) a matrix g(1:n,1:Nmax) and (ii) a vector tau(1:Nmax), as Nmax eigenfunctions and eigenvalues of a matrix constructed within fun. Now I want to get this output for all values withing a vector vec2(1:n). The simplest way is a for-loop
for i=1:n
[g(1:n,1:Nmax,1:n),tau(1:n,1:Nmax)] = fun(vec(1:n),Nmax,vec2(i))
end
This is however slow. Replacing it with a parfor-loop
parfor i=1:n
[g(:,:,i),tau(i,:)] = fun(vec(:),Nmax,vec2(i))
end
is quite a bit faster. I was wondering if there is a way to accelerate this even further by threading over the vector vec2? Somehow I cannot find the correct way without rewriting the function fun in several ways. Maybe the problem is that g is already a matrix, therefore fun(vec,Nmax,vec2') does not evaluate things in the correct dimension?
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Matt J
2020년 1월 27일
I was wondering if there is a way to accelerate this even further by threading over the vector vec2?
Not sure what you mean. The code as you've presented it already does divide vec2 into parallel pieces. Nothing in what you've shown makes inefficient use of parfor that I can see. Anything slow would be in the details of how fun is implemented.
If i write sin(vec+vec'), the output is a nxn matrix, where n is the length of vec. However within this notation I am limited to automatic threading over only two dimensions.
The extension would be
sin(vec+vec.'+ reshape(vec,1,1,[]));
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Philippe Lebel
2020년 1월 27일
0 개 추천
maybe take a look at arrayfun().
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도움말 센터 및 File Exchange에서 Parallel for-Loops (parfor)에 대해 자세히 알아보기
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