function handle in a loop

조회 수: 3 (최근 30일)
Sarah Kern
Sarah Kern 2020년 1월 22일
댓글: Walter Roberson 2020년 1월 23일
Hello,
I have the following objective function in my optimization matlab function block
if f_lag > 0 % decision braking or driving mode
fun =@(x) (A/SOC_1)*(b(1))^2+(A/SOC_2)*(x(2))^2+(A/SOC_3)*(x(3))^2+(A/SOC_4)*(x(4))^2+d_delay_1-(SW_1+x(5))+d_delay_2-(SW_2+x(6))+d_delay_3-(SW_3+x(7))+d_delay_4-(SW_4+x(8));
else
fun =@(x) ((B*M_reg_1)/SOC_1)*(1/(x(1))^2)+((B*M_reg_2)/SOC_2)*(1/(x(2))^2)+((B*M_reg_3)/SOC_3)*(1/(x(3))^2)+((B*M_reg_4)/SOC_4)*(1/(x(4))^2)+d_delay_1-(SW_1+x(5))+d_delay_2-(SW_2+x(6))+d_delay_3-(SW_3+x(7))+d_delay_4-(SW_4+x(8));
end
but because of code generation simulink/matlab, doesnt allow the function handles in the if loop.
Can someone help me what to do?
would be very glad, thank you!

채택된 답변

Walter Roberson
Walter Roberson 2020년 1월 22일
Provided that the two calculations return the same size of values, and provided that neither calculation ever returns inf or nan, then the general form
if condition
f = @(x) expression1
else
f = @(x) expression2
end
Can be rewritten as
f = @(x) (condition).*expression1 +
(~condition).*expression2
This is seldom the most efficient approach. Typically it would be more efficient to create both function handles and later test which one should be used.
  댓글 수: 2
Sarah Kern
Sarah Kern 2020년 1월 23일
Thank you very much, so like this?
f =@(x) (f_lag == 1).*(A/SOC_1)*(x(1))^2+(A/SOC_2)*(x(2))^2+(A/SOC_3)*(x(3))^2+(A/SOC_4)*(x(4))^2+d_delay_1-(SW_1+x(5))+d_delay_2-(SW_2+x(6))+d_delay_3-(SW_3+x(7))+d_delay_4-(SW_4+x(8));
+ (f_lag == -1).*((B*M_reg_1)/SOC_1)*(1/(x(1))^2)+((B*M_reg_2)/SOC_2)*(1/(x(2))^2)+((B*M_reg_3)/SOC_3)*(1/(x(3))^2)+((B*M_reg_4)/SOC_4)*(1/(x(4))^2)+d_delay_1-(SW_1+x(5))+d_delay_2-(SW_2+x(6))+d_delay_3-(SW_3+x(7))+d_delay_4-(SW_4+x(8));
It wont let me create both function handles, that's what I tried before.
Walter Roberson
Walter Roberson 2020년 1월 23일
That code looks plausible.
It will let you create both function handles: just store them in different variables and invoke the appropriate one. You might even be able to store them in a cell array and index that at (f_lag+3)/2

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추가 답변 (1개)

Sarah Kern
Sarah Kern 2020년 1월 23일
Thank you very much, so like this?
f =@(x) (f_lag == 1).*(A/SOC_1)*(x(1))^2+(A/SOC_2)*(x(2))^2+(A/SOC_3)*(x(3))^2+(A/SOC_4)*(x(4))^2+d_delay_1-(SW_1+x(5))+d_delay_2-(SW_2+x(6))+d_delay_3-(SW_3+x(7))+d_delay_4-(SW_4+x(8));
+ (f_lag == -1).*((B*M_reg_1)/SOC_1)*(1/(x(1))^2)+((B*M_reg_2)/SOC_2)*(1/(x(2))^2)+((B*M_reg_3)/SOC_3)*(1/(x(3))^2)+((B*M_reg_4)/SOC_4)*(1/(x(4))^2)+d_delay_1-(SW_1+x(5))+d_delay_2-(SW_2+x(6))+d_delay_3-(SW_3+x(7))+d_delay_4-(SW_4+x(8));
It wont let me create both function handles, that's what I tried before.

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