필터 지우기
필터 지우기

Why delete(fin​dobj(gca,'​type', 'patch')) is not working for erasing scattered points ?

조회 수: 4 (최근 30일)
Here's a simple snippet that shows that
delete(findobj(gca,'type', 'patch'))
is not working for erasing scattered points:
figure
x = [1,2,3,4]
y = [1,2,3,7]
scatter(x,y,50);
delete(findobj(gca,'type', 'patch')) % not working
%delete(findobj(gca,'SizeData', 50)) % does work
Uncommenting the last line solves the problem, but this is a workaround, or what ?

채택된 답변

Adam Danz
Adam Danz 2020년 1월 13일
편집: Adam Danz 2020년 1월 14일
"Why delete(fin​dobj(gca,'​type', 'patch')) is not working for erasing scattered points ?"
Because s = scatter(___) produces a scatter object, not a patch object.
Instead,
delete(findobj(gca,'type', 'scatter'))
Or better yet, use the scatter output which does not require the use of the axis handle and is more responsible since you're deleting a specific object rather than deleting all existing matches to an object type within the current axes.
s = scatter(. . .);
delete(s)

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Polygons에 대해 자세히 알아보기

제품


릴리스

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by