summation with for loop for all rows in another column

I had following data as attached

h = 1;

I_all size(3154*20)

So hmax = 20;

I1 = I_all(1,1) for first row and I1=I_all(2,1) for 2nd row and so on........

Need F_HL for all 3154 rows..........

[Rik]

What have you tried so far? Especially the version with a for loop seems easy to implement.

[MUKESH KUMAR]

h=1:20;
F_HL_N = 0;
for i=1:20
  
    F_HL_N = F_HL_N+(I_all(1,i)/I_all(1,1))^2* h(i)^2;
    
end
F_HL_D = 0;

for i=1:20
    
F_HL_D=F_HL_D+(I_all(1,i)/I_all(1,1))^2;

end
F_HL = F_HL_N/F_HL_D; % for first row 
% now want to do for all 3154 rows in for loop

Answer 1

[Raj]

You are almost there. Put the whole thing in another loop that runs accross all the rows and store F_HL for each row like this:

for ii=1:3154
h=1:20;
F_HL_N = 0;
for i=1:20
  
    F_HL_N = F_HL_N+(I_all(1,i)/I_all(1,1))^2* h(i)^2;
    
end
F_HL_D = 0;
for i=1:20
    
F_HL_D=F_HL_D+(I_all(1,i)/I_all(1,1))^2;
end
F_HL(ii) = F_HL_N/F_HL_D; % for iith row 
end

Done!