Format COMPACT not working

I was running a script and everything was in the compact format but I wanted to put format compact into the script so i could run the script anywhere and it would make sure it output answers in the compact format. As soon as I ran it with the new line "format compact" everything went to the loose format. I restarted matlab, opened a new file, restarted my computer, and deleted the format compact line. I changed my preferences to compact format but as soon as I run my script everything goes back to loose again. My script is literally like 30 lines and i only have one line in the entire thing that says format "......." it is the format compact line. No other lines say format anything. I cannot find an answer to this anywhere I am getting quite frustrated. I hope its just something dumb please help!

[David Goodmanson]

Hi Joshua, what happens with format('compact') ?

[Joshua Kreider]

Still Nothing it runs as if nothing was there

[John D'Errico]

Are you sure that your script does not call some other function of yours, that resets the format? We cannot see your script, so this is something we cannot know.

[Joshua Kreider]

This is my entire script as it is now. I know I need to fix the third grouping for "problem5" but the format is the problem here

tic

clear

clc

format compact

syms a b

problem1=((2/3)*exp(-a/2)*cos(b-1));

answer=subs(problem1,[a,b],[-0.23,2.7]);

answerproblem1a=double(answer)

syms c d

problem3=[c*d+1;c-2*d];

answer=subs(problem3,[c,d],[1.54,2.28]);

format

answerproblem3a=answer

syms e

problem5=(exp((-3*e)/(5))+(e*log(e+1)));

answer=subs(problem5,[e],[4.4]);

answerproblem5a=double(answer)

a=-0.23;

b=2.7;

c=1.54;

d=2.28;

e=4.4;

answerproblem1b=((2/3)*exp(-a/2)*cos(b-1))

answerproblem3b={c*d+1;c-2*d}

syms f(e)

f(e)=(exp((-3*e)/(5))+(e*log(e+1)));

df = diff(f,e);

df2 = df(2);

answerproblem5b=double(df2)

toc

[Joshua Kreider]

I feel so stupid guys I am so sorry. I had format written and i truly did not even see it. I kept skimming right over that part I apologize.

[John D'Errico]

Yep. Been there, done that.

[Joshua Kreider]

Yes haha. Really appreciate the help though