# Calculating results for Partial Sums

조회 수: 7(최근 30일)
Kyle Donk 10 Jan 2020
댓글: ME 18 Jan 2020
My question is:
Calculate the result and absolute error for each partial sum: N = 10, 160, and 640. You should use for-loops and not commands like symsum.
I keep on getting weird answes in Matlab and was wondering if my code was missing something:
%(a) Calculate the result and absolute error for each partial sum: N = 10, 160, and 640.
sum=0;
for N=[10 160 640]
for n=1:1:N
y=1/n^2
end
sum=sum+1
error=((pi^2)/6)-sum
end
disp(sum)
PLEASE DO NOT GIVE ME THE COMPLETE ANSWER TO THE QUESTION. I WOULD JUST LIKE AN EXPLANATION OF WHAT I AM DOING WRONG.

로그인 to comment.

### 채택된 답변

ME 10 Jan 2020
The main problem here is that you arent actually summing the y values as you go along. You are not adding y to the sum like you should, instead you are calculating all of the y values, ignoring them and adding 1 to the sum instead.
You would also probably be better off indexing your sum and error values so that you get one value for each of the Ns you input.
You have asked not to see the code so I haven't included it, but please comment below if you'd like me to add it!

#### 댓글 수: 5

표시 이전 댓글 수: 2
ME 17 Jan 2020
Did you manage to get this working in the end?
I still have the code if you haven't been able to figure it out.
Image Analyst 18 Jan 2020
The secondary problems are using sum and error for variable names. Don't use built-in function names for variable names.
ME 18 Jan 2020
Absolutely, this is a good point. It won’t cause any issues in this simple case but could be more problematic if this was to be built into something larger.

로그인 to comment.

### 추가 답변(0개)

이 질문에 답변하려면 로그인을(를) 수행하십시오.

Translated by