필터 지우기
필터 지우기

MOD bug? Or something else?

조회 수: 1 (최근 30일)
Dr. Seis
Dr. Seis 2012년 10월 4일
Seems to be a bug in MOD. The values inside the range from 0 to 1 that should result in MOD of 0 (or 0 to machine precision) for the example below (i.e., 0.4 and 0.8) are no where near 0.
>> [-2:.2:2;mod(-2:.2:2,.4)]'
ans =
-2.0000 0
-1.8000 0.2000
-1.6000 0
-1.4000 0.2000
-1.2000 0
-1.0000 0.2000
-0.8000 0.0000
-0.6000 0.2000
-0.4000 0.0000
-0.2000 0.2000
0 0
0.2000 0.2000
0.4000 0.4000
0.6000 0.2000
0.8000 0.4000
1.0000 0.2000
1.2000 0
1.4000 0.2000
1.6000 0
1.8000 0.2000
2.0000 0
I am running R2011a on UNIX... anyone else encounter this problem?

채택된 답변

Matt Fig
Matt Fig 2012년 10월 4일
편집: Matt Fig 2012년 10월 4일
Floating point arithmetic.... Look closely at the numbers.
x = [-2:.2:2];
fprintf('%16.16f\n',x)
You can read more about it here.
  댓글 수: 1
Dr. Seis
Dr. Seis 2012년 10월 4일
Yep... I was thinking this had nothing to do with floating point stuff. But if the value was very close to 0.4 (i.e., 0.4 +/- epsilon), the behavior of MOD would be very different if it was +epsilon versus -epsilon.
mod(0.39999999999,0.4) = 0.39999999999
vs.
mod(0.40000000001,0.4) = 0.00000000001
Looks like I will need to overload MOD

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Dr. Seis
Dr. Seis 2012년 10월 5일
This overloaded MOD function seems to overcome my issue:
function answer = mod(X,Y)
tol = 1e7;
X = round(X*tol)/tol;
Y = round(Y*tol)/tol;
answer = builtin('mod',X,Y);
end
*Note: I am dealing with numbers with less than 7 significant digits

카테고리

Help CenterFile Exchange에서 Introduction to Installation and Licensing에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by