How to extract elements form a vector in order to create an unknown number of sub-vectors?

Hello, I have a vector called M, in which there are several numbers. I need to divide it in some sub vectors (y) of different size without changing the order of the data in M. The subvector ends when it is reached a number lower than the previous. this one is the first number of the next subvector

M=[2.24;2.28;2.31;0.99;1.44;1.44;1.44;1.44;
    2.12;2.25;2.48;3.61;1.86;1.89;1.89;1.89;1.89;1.89;1.89];
for j=1:(length(M(:))-1)
if M(j)>M(j+1)
else      y(j)=M(1:j);
 end
end

Finally I should obtain the following vectors but the code doesn't work

y1=[2.24;2.28;2.31]

y2=[0,99;1.44;1.44;1.44;1.44;2.12;2.25;2.48;3.61]

y3=[1.86;1.89;1.89;1.89;1.89;1.89;1.89];

Answer 1

[Stephen23]

Here is one simple approach based on diff, cumsum, and accumarray:

>> M = [2.24;2.28;2.31;0.99;1.44;1.44;1.44;1.44;2.12;2.25;2.48;3.61;1.86;1.89;1.89;1.89;1.89;1.89;1.89];
>> X = cumsum([true;diff(M(:))<0]);
>> C = accumarray(X,M(:),[],@(v){v});
>> C{:}
ans =
   2.2400
   2.2800
   2.3100
ans =
   0.99000
   1.44000
   1.44000
   1.44000
   1.44000
   2.12000
   2.25000
   2.48000
   3.61000
ans =
   1.8600
   1.8900
   1.8900
   1.8900
   1.8900
   1.8900
   1.8900

You can access the contents of the cell array using indexing:

https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html

Using numbered variables is unlikely to be a good approach.

[Paolo Ottonelli]

thank you