How to make codegen concatenate strings
조회 수: 1 (최근 30일)
이전 댓글 표시
Using R2012a codegen, if I create the following m file:
function testStrCat()
path = char(zeros(1, 40));
fspec = char(zeros(1, 132));
coder.ceval('strcat', path, 'path');
coder.ceval('strcat', fspec, path);
coder.ceval('strcat', fspec, '/');
then build it as a C static library, I get the following output file:
1 /*
2 * testStrCat.c
3 *
4 * Code generation for function 'testStrCat'
5 *
6 * C source code generated on: Thu Oct 04 13:47:50 2012
7 *
8 */
9
10 /* Include files */
11 #include "rt_nonfinite.h"
12 #include "testStrCat.h"
13
14 /* Type Definitions */
15
16 /* Named Constants */
17
18 /* Variable Declarations */
19
20 /* Variable Definitions */
21
22 /* Function Declarations */
23
24 /* Function Definitions */
25
26 /*
27 * function testStrCat
28 */
29 void testStrCat(void)
30 {
31 char_T cv0[40];
32 int32_T i0;
33 char_T cv1[4];
34 static const char_T cv2[4] = { 'p', 'a', 't', 'h' };
35
36 char_T cv3[132];
37
38 /* 'testStrCat:2' path = char(zeros(1, 40)); */
39 /* 'testStrCat:3' fspec = char(zeros(1, 132)); */
40 /* 'testStrCat:5' coder.ceval('strcat', path, 'path'); */
41 for (i0 = 0; i0 < 40; i0++) {
42 cv0[i0] = '\x00';
43 }
44
45 for (i0 = 0; i0 < 4; i0++) {
46 cv1[i0] = cv2[i0];
47 }
48
49 strcat(cv0, cv1);
50
51 /* 'testStrCat:6' coder.ceval('strcat', fspec, path); */
52 for (i0 = 0; i0 < 132; i0++) {
53 cv3[i0] = '\x00';
54 }
55
56 for (i0 = 0; i0 < 40; i0++) {
57 cv0[i0] = '\x00';
58 }
59
60 strcat(cv3, cv0);
61
62 /* 'testStrCat:7' coder.ceval('strcat', fspec, '/'); */
63 for (i0 = 0; i0 < 132; i0++) {
64 cv3[i0] = '\x00';
65 }
66
67 strcat(cv3, '/');
68
69 /* coder.ceval('strcat', fspec, file); */
70 }
71
72 /* End of code generation (testStrCat.c) */
Notice that each time I try to concatenate a string, it zeros out the destination string first. Am I doing this wrong?
Thanks Sean
댓글 수: 0
채택된 답변
Kaustubha Govind
2012년 10월 4일
I think you'll get closer to what you want by using the right MATLAB Coder directives:
function testStrCat()
path = coder.nullcopy(char(zeros(1, 40)));
fspec = coder.nullcopy(char(zeros(1, 132)));
coder.ceval('strcat', coder.ref(path), ['path' 0]); %null-termination
coder.ceval('strcat', coder.ref(fspec), path);
coder.ceval('strcat', coder.ref(fspec), '/');
Now the code looks like:
void testStrCat(void)
{
char_T path[40];
char_T fspec[132];
char_T cv0[5];
int32_T i0;
static const char_T cv1[5] = { 'p', 'a', 't', 'h', '\x00' };
for (i0 = 0; i0 < 5; i0++) {
cv0[i0] = cv1[i0];
}
strcat(path, cv0);
strcat(fspec, path);
strcat(fspec, '/');
}
I don't know how you can avoid that extra copy for the string "path".
댓글 수: 2
Kaustubha Govind
2012년 10월 5일
Sean: Strange I was able to search our online documentation to find coder.nullcopy. Not sure if you've seen the latest Documentation Center that was introduced in R2012b, but I think topics are now easier to navigate. I hope this will help you better than the old documentation format!
(Also, if you're satisfied with my answer, could you please accept it? Thanks!)
추가 답변 (0개)
참고 항목
제품
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!