help speeding up an incrementing loop
이전 댓글 표시
hi,
i'm trying to calculate some correlation factors using nested loop.
the equation im implementing is:

my parameters are:
H - 200*256 matrix
P - 200*370,000 matrix
AES_key_opt = 256
read_trc = 370,000
raw = 256*370,000 (calculated matrix)
now, i know i'm dealing with alot of data, but my question is if it possible to speed up somehow the relevant lines from the profiler?
relevant code part:
% calculates the pearson correlation mat "raw" size "AES_key_opt","l_trc"
for i = 1:AES_key_opt
for j = 1:read_trc
% claculate H' and P' for every "i" and "j"
H_avg = H_C_sum(i)/n_trc;
P_avg = P_C_sum(j)/n_trc;
% numerator calculation
numerator=0;
for k = 1:n_trc
numerator = numerator + (H(k,i) - H_avg)*(P(k,j) - P_avg);
end
% denumerator calculation
denom_H = 0;
denom_P = 0;
for k = 1:n_trc
denom_H = denom_H + (H(k,i) - H_avg)^2;
denom_P = denom_P + (P(k,j) - P_avg)^2;
end
denominator = sqrt((denom_H*denom_P));
% pearson correlation mat calculation
raw(i,j) = numerator/denominator;
end
end
profiler:

I would be thankful for any help or tips
thanks
답변 (2개)
Walter Roberson
2019년 12월 26일
0 개 추천
You have defined that you must use nested loops. That is what is loosing you most of your efficiency when you could be vectorizing.
You can make minor tweaks like extracting the (:,i) slice near the top of the for i loop and indexing that at k instead of indexing the array at (k,i) inside the triple loop, but I am not convinced that it would help in any meaningful way.
댓글 수: 3
Walter Roberson
2019년 12월 26일
Though as Vladimir points out, pre-allocating raw() is recommended.
Image Analyst
2019년 12월 26일
Because he said "i'm trying to calculate some correlation factors using nested loop." I don't think that implied a definite requirement. It was just the way he first decided to tackle the problem. I think he's open to other, faster approaches.
Walter Roberson
2019년 12월 26일
The bar variables can be found by using mean()
Your denominators are closely related to the standard deviation. You do have sqrt() of the product of two terms, but because the terms are independent, you can separate the terms, sqrt(A) * sqrt(B), and the calculations being done individually then would be N * std(A,1) -- notice the second parameter of 1 to get the proper division (or you could use std() but change what you multiply by.)
Vladimir Sovkov
2019년 12월 26일
At the first glance, you can replace
numerator=0;
for k = 1:n_trc
numerator = numerator + (H(k,i) - H_avg)*(P(k,j) - P_avg);
end
by
numerator = (H(1:n_trc,i) - H_avg)'*(P(1:n_trc,j) - P_avg);
as well as
denom_H = 0;
denom_P = 0;
for k = 1:n_trc
denom_H = denom_H + (H(k,i) - H_avg)^2;
denom_P = denom_P + (P(k,j) - P_avg)^2;
end
by
denom_H = (H(1:n_trc,i) - H_avg)'*(H(1:n_trc,i) - H_avg);
denom_P = (P(1:n_trc,j) - P_avg)'*(P(1:n_trc,j) - P_avg);
You can use ":" instead of "1:n_trc" if the corresponding array sizes exactly equal to n_trc.
You should also preallocate "raw" before the loop in order to avoid its sequential resizing: raw=zeros(...,...).
H_avg and P_avg are also recommended to compute before the loop as vectors, otherwise you compute the same values several times repeatedly.
Probably, fufther optimization is also possible.
Not all variables have clear sense (H_C_sum, P_C_sum, etc).
댓글 수: 5
tamir elazari
2019년 12월 26일
편집: tamir elazari
2019년 12월 26일
Walter Roberson
2019년 12월 26일
These changes violate the stated constraint that nested loops must be used.
tamir elazari
2019년 12월 26일
Vladimir Sovkov
2019년 12월 26일
If no loops are necessary, I think that the matrix of Pearson statistics can be computed by a single line of code:
raw=normalize(H)'*normalize(P);
Vladimir Sovkov
2019년 12월 28일
편집: Vladimir Sovkov
2019년 12월 28일
raw=normalize(H)'*normalize(P)/size(H,1);
카테고리
도움말 센터 및 File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!