Change color of stacked bars according to values

조회 수: 16 (최근 30일)
Yasmin Samy
Yasmin Samy 2019년 12월 18일
댓글: Yasmin Samy 2019년 12월 19일
Hello,
I am trying to plot a stacked bar chart, where each bar has a color shade depending on values from another vector. I tried to use CData but failed..
bin_width is the bar widths that made the stacked bar chart with.
However, the color shade of each bar should depend on the values in mtot. I'm having trouble creating a new colormap that can be applied on my bar chart.
%reading input
mtot=table(3,:); %this is an array of size (1 x 32), these are the values that should define the color of the bars
% %tried to set a new color bar
% caxis([min_m max_m]);
% colorbar
% hold on
%plotting of stacked bar chart
% barcolor=c(size(mtot,2));
f=barh(0,bin_width','stacked','FaceColor','flat');
set(gca,'XScale','log');

답변 (1개)

Xin Li
Xin Li 2019년 12월 19일
Hi, Yasmin,
My understanding of your question is that you want to plot a horizontal stacked bar chart
with customized color for each bar. One way to achieve your goal is by setting 'FaceColor'
parameter for each bar using a for loop.
Here is an example, hope it is helpful.
load count.dat;
y = count(1:4,:); % y is a 4-by-3 matrix
width = 0.7;
colors = {'r', 'g', [0,0.5,0.5]}; % customized colors wrapped in a cell array, element could be either a color mark or a RGB vector
% set up colors
h = barh(y, width, 'stacked', 'LineStyle',':');
for i = 1 : 3
h(i).FaceColor = colors{i};
end
figure.jpg
For more information, please refer to barh function document.
  댓글 수: 3
Xin Li
Xin Li 2019년 12월 19일
편집: Xin Li 2019년 12월 19일
It is easy to generate a clolor map with function cool.
Say, if you want to have 40 colors, just do
colors = cool(40);
assume mtot(1,1) = 3, then colors(3, :) is the actual color for that bar.
Yasmin Samy
Yasmin Samy 2019년 12월 19일
Im sorry but can you clarify further. My problem is how to connect the values of mtot to colors that the bar takes accordingly. How do you write that in code?

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