Cycle counting from 0
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I have a matrix [ 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 1 1 0 0 0 0] for exemple
I'd like to have an outing:
2 x 4 "0" in succession
2 x 2 "0" in succession
1 x 3 "0" in succession
How to program it
Thank you.
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Image Analyst
2019년 12월 11일
편집: Image Analyst
2019년 12월 11일
I have no idea what you want. What is an "outing"? Do you mean output? If so, what is the output array you want? I can't tell from your word descriptions. Type it out in numbers like you did for the input matrix.
Stephen23
2019년 12월 12일
stefan's "Answer" moved here:
With this matrix : [ 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 1 1 0 0 0 0 1 1 1 1 1 0 0 0 0 0 ]
I would have liked to have this matrix :
|5 2|
|6 1|
|4 1|
With the 1st column the number of successive 0
With the 2nd column the number of the sequence
thanks
채택된 답변
Stephen23
2019년 12월 12일
편집: Stephen23
2019년 12월 12일
>> M = [0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,1,1,1,0,0,0,0,1,1,1,1,1,0,0,0,0,0];
>> D = diff([false;M(:)==0;false]);
>> L = find(D<0) - find(D>0);
>> [U,~,X] = unique(L,'stable');
>> V = histc(X,1:max(X));
>> Z = [U(:),V(:)]
Z =
5 2
6 1
4 1
댓글 수: 7
Stephen23
2019년 12월 14일
편집: Stephen23
2019년 12월 14일
"I have a vector that can have values from 1 to 15. I would like to know the number of times for all the possible changes: for example:"
from 1 to 2
from 2 to 11
from 14 to 3
....
None of your provided data includes the values 11 or 14, so you are asking me to help you on an unknown algorithm with unknown data. Sorry, but my magic crystal ball is not working today.
"from 2 to 3 and from 3 to 4, I don't have the couples (1,2) and (2,3)."
Well, that makes two of us, because I don't have them either! Nor do you explain what they are, or how they relate to 1, 2, 11, 14, and 3 from your previous comment, or the binary data of your original question.
One clear explanation of the method/algorithm (complete with input and output example data) would actually mean that you get the help that you are looking.
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Akira Agata
2019년 12월 12일
How about the following?
x = [0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 1 1 0 0 0 0 1 1 1 1 1 0 0 0 0 0];
str = num2str(x')';
c = regexp(str,'0+','match');
len = cellfun(@numel,c);
output = [(1:max(len))', accumarray(len',1)];
The result becomes like this:
>> output
output =
1 0
2 0
3 0
4 1
5 2
6 1
댓글 수: 2
Akira Agata
2019년 12월 12일
You mean, the order is also important?
My output is same as what you expected, except the order of rows and including 0 sequence cases (such as 1~3 consecutive zeros).
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