How can I make my high pass filter more accurate?
조회 수: 3 (최근 30일)
이전 댓글 표시
Hello everyone,
So, I am doing a project with a sound file of my voice and applying some filters to it and finding the fourier transforms.
My code (just a little part) is:
[y,Fs] = audioread('myvoice.m4a');
L = length(y);
f = Fs*(0:(L/2))/L; %frequency
y_HPF_270 = highpass(y,270,Fs);
%270Hz
%plot fourier transform of HPF
%set up
% Compute the two-sided spectrum P2. Then compute the single-sided spectrum P1 based on P2 and the even-valued signal length L.
P2_HPF270 = abs(yf_HPF_270/L);
P1_HPF270 = P2_HPF270(1:L/2+1);
P1_HPF270(2:end-1) = 2*P1_HPF270(2:end-1);
%plot
subplot(3,2,6);
plot(f,P1_HPF270)
title('Single-Sided Amplitude Spectrum of HPF 270Hz')
xlabel('f (Hz)')
ylabel('|P1(f)|')
From what I understand from High Pass filters is that i filters the frequencies that are below a cutoff frequency. If my cutoff frequency is 270 Hz, why do I get still frequencies below 270?
The fourier Transform graph taht I get is:
댓글 수: 0
채택된 답변
Ridwan Alam
2019년 12월 11일
편집: Ridwan Alam
2019년 12월 11일
If my cutoff frequency is 270 Hz, why do I get still frequencies below 270?
Unless it's an ideal highpass filter, most filter implementations show a transition band where the attenuation starts to take effect. You can find more details here:
To get steeper response, try this:
highpass(y,270,Fs,'Steepness',0.99,'StopbandAttenuation',100)
댓글 수: 0
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Fourier Analysis and Filtering에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!