Multiple outputs from anonymous function
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I have a function of the following form
function [out1, out2] = demo_fcn( in )
out1 = in(1);
out2 = in(2);
end
which gets called by
[out1, out2] = @(x) demo_fcn(x);
but anonymous functions are not allowed more than one outputs. This is clearly a simplified example, the application is for a nonlinear programming problem where out1 is the objective function and out2 is the gradient calculation. I am not sure how I can structure this differently or in a way which is acceptable by MATLAB syntax.
Note the error messge is
Only functions can return multiple values.
댓글 수: 3
Guillaume
2019년 12월 10일
So, I'm a bit unclear on what you are asking.
As pointed out by Stephen, anonymous functions can return more than one output (as long as the function delegates the actual processing to a function that returns more than one output).
Yes, some functions such as your demo_fun can't be implemented as an anonymous function since it's made of two statements and anonymous functions in matlab are limited to one non-branching statement. However, you're never forced to use anonymous functions, they're just syntactic sugar that can always be replaced by named functions. You can pass a handle to your demo_fun to fmincon and others, so why can't you use demo_fun as you have written it?
답변 (5개)
Pritesh Mody
2022년 5월 4일
편집: Pritesh Mody
2022년 5월 4일
The built-in "deal" function allows this. There is an example in the help for deal.
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Shengchao Lin
2024년 1월 30일
+1 on this. There is a documented behavior here:
Star Strider
2019년 12월 10일
One option is to have the two outputs to one vector, then separate them in a subsequent assignment:
demo_fcn = @(in) [in(1) in(2)];
in = rand(2,1)
Out = demo_fcn(in)
Out1 = Out(1)
Out2 = Out(2)
This works, however I cannot tell if it does what you want it to do.
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Star Strider
2019년 12월 10일
O.K.
The approach I used would clearly not allow concatenation such as that unless the outputs of the two sub-functions were in cell arrays. That adds the additional complication of recovering the double array from the cell array, however that is not diffcult.
I encourage you to experiment with that approach.
Benjamin Pepper
2024년 11월 13일 16:24
Was this solved in the end? I'm trying to implement the same code.
gotjen
2021년 6월 25일
편집: Walter Roberson
2022년 5월 4일
Hey Morten, even though its years later I want to give you my solution to this problem. I use the matlab function disperse ( https://www.mathworks.com/matlabcentral/fileexchange/33866-disperse ) which is availble on the File Exchange but should absoutely become a built in function.
disperse splits arrays into multiple output arguments. You can use it to conveniently get multple outputs from an anonymous function
f = @(x) disperse( [x, 2*x] )
[a, b] = f(1:10)
% a = [ 1 2 ... 10 ];
% b = [ 2 4 ... 20 ];
Nice pet example but lets do something useful with it.
Say we have a structure array, and we want to get the 3rd element from two vector members of that structure. We want to get them out as two arrays
% data is some large data structure we use to pass around parameters for
% our model.
[A, B] = arrayfun( @(s) disperse([ s.wavelength(3), s.absorption(3)]), data);
This one-liner avoids some ugly for-loop when all we want to do is slice our data structure in an unusual way.
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Stephen23
2022년 12월 18일
One-liner without any third party functions:
f = @(x) deal(x, 2*x);
[a, b] = f(1:10)
Renwen Lin
2022년 12월 18일
try this
@(x1,x2)deal(x1+1,x2+1)
% T2 = grouptransform_easy(T, {'HA','HB'},@(x1,x2)deal(x1+1,x2+1),{'Grade','Name'},["Province","City"]);
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Steven Lord
2024년 11월 13일 16:36
When you define an anonymous function, assign it to one output.
f = @(x) svd(x, "econ") % Define f
When you call an anonymous function you can call it with however many outputs you want (that the code inside the anonymous function supports.) So since svd can return up to three ouptuts:
A = [1 2 3 4; 5 6 7 8; 9 10 11 12];
[U, S, V] = f(A) % Call f
[checkU, checkS, checkV] = svd(A, "econ") % Show that f did call svd with 3 outputs
This code from the original question didn't work because it tried to specify multiple outputs when defining the function and that won't work. [I'm commenting it out so it doesn't error when I run the code in my answer.]
% [out1, out2] = @(x) demo_fcn(x);
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