# Interval where values are greater than treshold

조회 수: 1(최근 30일)
Lucas Russi 10 Dec 2019
Commented: Lucas Russi 10 Dec 2019
Hi everyone
Logic = Data > Treshold
I now need to know what the intervals are where the treshold is exceeded
Logic = [1 1 1 0 0 0 1 1 0 1]
Desired_Output = [1 3;7 8;10 10]
So - from 1 to 3, from 7 to 8 aswell as 10
I can't think of a good way to do this.

로그인 to comment.

### 채택된 답변

Stephen Cobeldick 10 Dec 2019
>> B = find([true;diff(Logic(:))>0]);
>> E = find([diff(Logic(:))<0;true]);
>> M = [B,E]
M =
1 3
7 8
10 10

#### 댓글 수: 1

Lucas Russi 10 Dec 2019
gracias <3

로그인 to comment.

Jeremy Marcyoniak 10 Dec 2019
I believe you are looking for the find command.
find(Logic)

#### 댓글 수: 3

Lucas Russi 10 Dec 2019
find(Logic) = [1 2 3 7 8 10]
not exactly - I'm aware of find; there's one more step to get to what I put as my desired Output .. and there's the issue
Jeremy Marcyoniak 10 Dec 2019
You could use
diff
to determine adjacent numbers and drop the intermediate numbers appropriately
Lucas Russi 10 Dec 2019
Thanks for participating :)
idx = find(Logic)
idx(end+1) = 0
idx(diff(idx) ~= 1)
would be the indices that mark the end of the interval - but what about the start ?

로그인 to comment.

이 질문에 답변하려면 로그인을(를) 수행하십시오.

Translated by