Forming loop to simplify codes

조회 수: 4 (최근 30일)
Johnny
Johnny 2019년 12월 10일
답변: per isakson 2019년 12월 11일
Can you help me use loop to simplify the following code and produce the same graph?
c=5
dista=log([12:-1:8 6 4:-1:1]+retint)
distb=log([14:-1:9 6 3:-1:1]+retint)
distc=log([16:-1:10 6 2:-1:1]+retint)
etaa = exp(-c*abs(dista-dista(:)));
discrima = 1./sum(etaa,1)
etab = exp(-c*abs(distb-distb(:)));
discrimb = 1./sum(etab,1)
etac = exp(-c*abs(distc-distc(:)));
discrimc = 1./sum(etac,1)
figure (11)
hold on
plot(discrima,'-mo','Displayname','gap = 12(8,6,4)1')
plot(discrimb,'-ro','Displayname','gap = 14(9,6,3)1')
plot(discrimc,'-bo','Displayname','gap = 16(10,6,2)1')
axis([0 length(dista) 0 1])
xlabel('Serial Position','fontsize',14)
ylabel('Discriminability','fontsize',14)
title({'SIMPLE Memory Model'...
'\fontsize{9}\color{blue}Length = 10; Various Gaps'})
lgd = legend ('Location','northwest');
lgd.NumColumns = 1;
lgd.FontSize = 9;
set(gcf, 'color', 'white');
hold off

채택된 답변

per isakson
per isakson 2019년 12월 11일
"produce the same graph" The code below produces the same graph.
However
  • it may be disputed whether it's simpler
  • less intermediate results are saved
%%
c = 5;
retint = 0;
%%
cac = { '-go','Displayname','gap = 12(8,6,4)1'
'-ro','Displayname','gap = 14(9,6,3)1'
'-bo','Displayname','gap = 16(10,6,2)1' };
num = [ [12:-1:8,6,4:-1:1]+retint
[14:-1:9 6 3:-1:1]+retint
[16:-1:10 6 2:-1:1]+retint ];
%%
figure(11);
hold on
%%
for jj = 1 : 3
dist = log(num(jj,:));
eta = exp(-c*abs(dist-reshape(dist,[],1)));
discrim = 1./sum(eta,1);
plot( discrim, cac{jj,:} )
end
%%
axis([0,length(dist(1,:)),0,1.02*max(max(discrim))])
xlabel('Serial Position','fontsize',14)
ylabel('Discriminability','fontsize',14)
title({'SIMPLE Memory Model'...
'\fontsize{9}\color{blue}Length = 10; Various Gaps'})
lgd = legend ('Location','northwest');
lgd.NumColumns = 1;
lgd.FontSize = 9;
set(gcf, 'color', 'white');
hold off

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by