could anyone help me to display the values in the matrix which are greater than the average value for the following code

조회 수: 4 (최근 30일)
code:
A=[3.3734 5.1245 4.3729 2.8406 6.5283 4.8144 2.9305 6.8098 2.8633 4.2790 6.3190 5.7503 5.4061 6.0009 9.3549]
B=sum(A)
C=numel(A)
D=B/C
When i run the code the value of D is found to be 5.1179
so i want to display A such that the values present in A should be greater than 5.1179 and hence
A = [5.1245 6.5283 6.8098 6.3190 5.7503 5.4061 6.0009 9.3549]
could anyone please help me on this.

채택된 답변

Stephan
Stephan 2019년 12월 4일
편집: Stephan 2019년 12월 4일
B, C and D are not needed, if you use the inbuilt function mean:
A=[3.3734 5.1245 4.3729 2.8406 6.5283 4.8144 2.9305 6.8098 2.8633 4.2790 6.3190 5.7503 5.4061 6.0009 9.3549]
A = A(A>mean(A))
results in:
A =
Columns 1 through 8
3.3734 5.1245 4.3729 2.8406 6.5283 4.8144 2.9305 6.8098
Columns 9 through 15
2.8633 4.2790 6.3190 5.7503 5.4061 6.0009 9.3549
A =
5.1245 6.5283 6.8098 6.3190 5.7503 5.4061 6.0009 9.3549
  댓글 수: 1
jaah navi
jaah navi 2019년 12월 4일
with respect to the above code the mean(A) is 5.1179
so I need to select the values which are greater than 5,which means values from 6 - 6.5283 6.8098 6.3190 6.0009 and values from 9-9.3549 should be selected.
Could you please help me on this.

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Inho Kim
Inho Kim 2019년 12월 4일
Hi Jaah,
You can use logical index.
ind = A > D; % find indices when each value of A is bigger than D
AA = A(ind); % extract element from A vector
Thanks,
Inho

카테고리

Help CenterFile Exchange에서 Direction of Arrival Estimation에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by