How can I classify data based on two columns??

hi ,

I have a data as shown below, I need to classify it based on the rho and theta.

I am looking to plot complete line by extract start and end of point for lines . so i need to classfy as follw:

groups : have the same rho and inside it two groups : 1- when theta = -90 which is hirozental line.

2- when theta = 0 which is vertical line.

I have tried that but there somthing wrong which ('Index exceeds the number of array elements (19)')

could you please help me??

[Image Analyst]

Yes, if you supply your code and the exact error message. Perhaps you took a list of indexes and used it on the columns instead of the rows or something. Who knows???

[Mohammed Alammar]

%%

% reconstructedImage_Measurements of lines;

% Number of tiles in the vertical (time) dimension

Nt = 500;

% Number of tiles in the horizontal (frequency) dimension

Nf = 1000;

wz=[1;Nf];

hz=[1;Nt];

for m = 1: length(lines)

if (lines(m).theta==lines(m+1).theta) && (lines(m).rho==lines(m+1).rho)

XY=[lines(m).point1;lines(m+1).point2];

if XY(1,1)==XY(2,1) && (lines(m).theta ==-90)

XY(:,2)= wz;

elseif XY(1,2)==XY(2,2) && (lines(m).theta ==-90)

XY(:,1)= wz;

elseif XY(1,1)==XY(2,1) && (lines(m).theta ==0)

XY(:,2)= hz;

elseif XY(1,2)==XY(2,2) && (lines(m).theta ==0)

XY(:,1)= hz;

end

else

XY=[lines(m).point1;lines(m).point2];

end

plot(XY(:,1),XY(:,2),'LineWidth',2,'Color','red');

end

[Luna]

Can you provide the data as a .mat file attached?

Answer 1

[Luna]

Your error caused from the line for loop. You have 19 elements but m+1 will be 20.

for m = 1:length(lines)-1
    ...
end

This will fix your problem.