I currently have a script which initiates a "for" loop early on, creating a vector array 3x50.
Later on, I attempt to generate a new 3x50 vector using conditional statements so that when the value is above a certain critical value, then the element returned corresponds to the i,j of a one vector, and if it's below, it returns the i,j of a different vector.
for j=1:3
Qr(j)
for i=1:50
if Pc(i,j)>=P0(i,j)
P12(i,j)=Pc(i,j)
else P12(i,j)=P0(i,j)
end
end
Could someone please explain a way to accomplish this?
Thanks.

 채택된 답변

Steven Lord
Steven Lord 2019년 11월 29일

0 개 추천

Use the max function with two inputs.

추가 답변 (1개)

Geoff Hayes
Geoff Hayes 2019년 11월 29일

0 개 추천

Zachary - you seem to be missing an end in your code. Perhaps try
for j=1:3
Qr(j)
for i=1:50
if Pc(i,j)>=P0(i,j)
P12(i,j)=Pc(i,j)
else
P12(i,j)=P0(i,j)
end
end
end

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도움말 센터File Exchange에서 Logical에 대해 자세히 알아보기

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2019년 11월 29일

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2019년 11월 30일

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