MATLAB Answers

how to speed my code up

조회 수: 1(최근 30일)
cglr
cglr 16 Nov 2019
댓글: Daniel M 17 Nov 2019
Hello everone,
Here, line 4 and 5 is called 5525575680 times and they last 280 and 230 seconds in order. May I speed it up, how can I use it more efficient ?
1 function [utilization] = totalUtilization(myArray, periodNumber, count, LPP)
2 duration = 0;
3 for i = 1:count
4 duration = duration + myArray(periodNumber, i);
5 end
6 utilization = duration / LPP;
7 end
Thanks in advance.

  댓글 수: 1

cglr
cglr 16 Nov 2019
Because, I still can't get used to ability of MATLAB :) .
You are exactly true and no need to loop for sum or etc. I wrote the function taking into account to your comment:
utilization = sum(myArray(periodNumber,:)) / LPP;
Thank you so much.

로그인 to comment.

채택된 답변

Daniel M
Daniel M 16 Nov 2019
편집: Daniel M 16 Nov 2019
Why do you need a loop to compute a sum? Just replace the entire function with
utilization = sum(myArray(periodNumber, 1:count)) / LPP;
And if count is equal to the number of columns of myArray, replace "1:count" with just ":" to avoid making an extra temporary index.
If periodNumber happens to be a vector, then include the number 2 as the dimension input into sum.

  댓글 수: 4

표시 이전 댓글 수: 1
Daniel M
Daniel M 16 Nov 2019
What is table in this code? Is it an empty table using the table() function? https://www.mathworks.com/help/matlab/ref/table.html
Is it a table named table? Because you're not accessing any of its properties.
If it is a regular array then no need for a loop, just replace "i" with ":"
cglr
cglr 17 Nov 2019
actually table is a regular array with the size (period,telCount). And I can ask the question in a better way as seen below:
x = zeros(period,1);
for i=1:period
x(i,1) = sum(table(i,1:telCount));
end
Here what I want is, sum all column for each row and write result to x array.
Daniel M
Daniel M 17 Nov 2019
You really enjoy writing loops! But you don't need to. Look up the documentation for the sum function. It shows you how to do just that.

로그인 to comment.

추가 답변(0개)

이 질문에 답변하려면 로그인을(를) 수행하십시오.

태그


Translated by