Finding transpose of values.
조회 수: 1 (최근 30일)
이전 댓글 표시
ts = xlsread('ArrowHead_TRAIN.xlsx');
for i = 1:100
b=20
p=ts(i,:);
n= numel(p);
Z=mat2cell(p,diff([0:b:n-1,n]));
A=transpose(Z);
celldisp(A)
end
I want to find the transpose of Z values.I need the elements of Z in an array order.I used transpose,but not working.How can I get the elements of Z in an array form.Please help me.
댓글 수: 0
채택된 답변
Walter Roberson
2019년 11월 6일
ts = xlsread('ArrowHead_TRAIN.xlsx');
for i = 1 : size(ts,1)
b = 20;
p = ts(i,:);
n = numel(p);
Z = mat2cell(p, 1, diff([0:b:n-1,n]));
A = cellfun(@transpose, Z, 'uniform', 0);
celldisp(A)
end
댓글 수: 2
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Matrices and Arrays에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!