I have two sets
X Y
1 2
3 6
4 7
5 8
I have to find highest value in category Y which is 8, after finding that 8 is the highest value I have to call value 5 in category X to from a matrix [ 5 8].
I know how to find the largest value, but I don’t know how to call 5 from X category.
Please can someone help me in call the specified value.

 채택된 답변

galaxy
galaxy 2019년 10월 25일

1 개 추천

Let 's try
X = [1 3 4 5];
Y = [2 6 7 8];
[max_val, idx] = max(Y);
X_idx = X(idx);

댓글 수: 7

sampath kumar punna
sampath kumar punna 2019년 10월 25일
Y
1 3
5 6
3 2
7 9
8 5
if Y is matrix , in the the second column we have values 2 and 5 , i want to call the row which is having value 2 and 5 in second column and from a new matrix
[ 3 2
8 5 ]
like this
galaxy
galaxy 2019년 10월 25일
out = Y(find(Y(:,2) == 2 | Y(:,2) == 5 ), :);
Please accept my answer.
sampath kumar punna
sampath kumar punna 2019년 10월 25일
Y = [1 7
3 9
11 12
15 18
22 12
12 23
15 19
10 22
17 28
111 123]
z= [ 9 12 18 12 23 19 22 28 123]
for i= 1: length(z)
out(i) = Y(find(Y(:,2) == z(:,i)))
end
this code shows some error can you fix this
galaxy
galaxy 2019년 10월 25일
I can't believe that after I anwser for you, you accept your anwser.
I think you are unkind person. So I will not support you even it is very easy.
sampath kumar punna
sampath kumar punna 2019년 10월 25일
im really sorry galaxy, i din't know that i have accepted my answer i thought i accepted your, i just saw my mistake and removed mine and accpected your. accepting my answer was not intentional, hope you understand.
sampath kumar punna
sampath kumar punna 2019년 10월 25일
by any chance can you fix this error
Y = [1 7
3 9
11 12
15 18
22 12
12 23
15 19
10 22
17 28
111 123]
z= [ 9 12 18 12 23 19 22 28 123]
for i= 1: length(z)
out(i) = Y(find(Y(:,2) == z(:,i)))
end
this code shows an error while executing (Unable to perform assignment because the left and right sides have a different number of
elements.)
can anyone please fix this error
thanks
galaxy
galaxy 2019년 10월 25일
Let 's try:
find_idx = find(Y(:,2) == z(1));
for i= 2: length(z)
find_idx = vertcat(find_idx, find(Y(:,2) == z(i)));
end
out = Y(unique(find_idx), :);
you can try with other z:
example:
z= [ 9 12 18];
out =
3 9
11 12
15 18
22 12

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추가 답변 (1개)

sampath kumar punna
sampath kumar punna 2019년 10월 25일

0 개 추천

what if i have to call 7 from y and 4 from x

카테고리

도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

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2019년 10월 25일

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2019년 10월 25일

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