Hello,
I am trying to create a matrix by several means, using linespace, using matrix notation and stating every element. For some reason the results obtained are not equal for some of the values in the matrix:
categ1=linspace(0.85,1.35, 51)
categ2=[0.85:0.01:1.35]
categ3=[0.85 0.86 0.87 0.88 0.89 0.9 0.91 0.92 0.93 0.94 0.95 0.96 0.97 0.98 0.99 1 1.01 1.02 1.03 1.04 1.05 1.06 1.07 1.08 1.09 1.1 1.11 1.12 1.13 1.14 1.15 1.16 1.17 1.18 1.19 1.2 1.21 1.22 1.23 1.24 1.25 1.26 1.27 1.28 1.29 1.3 1.31 1.32 1.33 1.34 1.35]
categ1==categ2
categ2==categ3

답변 (1개)

Daniel M
Daniel M 2019년 10월 21일

0 개 추천

The results are equal up to double precision. Look at this:
max(abs(categ1-categ2))
% ans =
% 2.22044604925031e-16
eps
% ans =
% 2.22044604925031e-16
So the values are equal up to the limit that the computer can differentiate between them.
It seems that linspace and colon have slightly different implementations. If you need something with higher precision, then look into John D'Errico's VPI toolbox.

댓글 수: 2

The problem is that when I create the matrix whit linspace and colon and later try to find the colation of the value equal to 1.2 get an empty matrix. Any idea of how can I solve that issue?
>> categ1=linspace(0.85,1.35, 51);
categ2=[0.85:0.01:1.35];
find(categ1==1.2)
find(categ2==1.2)
ans =
1×0 empty double row vector
ans =
1×0 empty double row vector

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질문:

2019년 10월 21일

편집:

2019년 10월 22일

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