How to get mean across cell array of arrays different size?

Dear All, need your help ;) !

I have 1x5 cell array of arrays different size, like this :

myData = {{9×119×11},{6×119×11},{8×119×11},{9×119×11},{7×119×11}}

Across all of them , I need to find one avarage Array , like this : avrData = {9×119×11} .

I have tried next one (seebelow), but doubt if this is correct???

Thanks in advance!

myData = {{9×119×11},{6×119×11},{8×119×11},{9×119×11},{7×119×11}}

% with NaN I make the same size

for k = 1:length(myData)

m = size(myData{k},1);

myDatal{k}(m+1:9,:,:) = NaN; % with NaN I make the same size

end

% I summarize all of new Arrays

sum = myData{1};

for i = 2:length(myData)

sum = sum + myData{i};

end

% here is mean

meanData = sum ./ length(myData));

[Guillaume]

Does it even make sense to pad the shorter matrices with NaN. Why is it row 6 or the 1st array that is averaged with row 6 of the 2nd array and not for example row 8 of the first array?

You're padding at the end but you could be padding at the beginning or evenly either side. All of these would give you different result, so why is padding at the end chosen?

Answer 1

[KALYAN ACHARJYA]

Might be following example help you

cell1=rand(3,3,3);
cell2=rand(2,3,2);
cell3=randi(10,2,2)
data={cell1,cell2,cell3}; % Just an example
avg_data=zeros(1,length(data));
for i=1:length(data)
    data1=data{i};
    data1=data1(:);
    avg_data(i)=mean(data1);
end
avg_data

[IM]

Thanksso much Kalyan for your answer! I wil try it.