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Question about making a function file with vectors and variables
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Question deleted by James. Partially restored by Matt Fig:
a part of my program has syntax that looks like this,
for n=1:1:A1 if (Z(n)<3 | Z(n)>9 | Z(n)~=Z(n)) disp('One or more of the element/s is/are not included.'); return;
elseif ~isnumeric(Z(n)) disp('There is error') return; end
so if i enter:
function_name ([3 4 A], [4 5 6])
matlab says: Undefined function or variable 'A'.
댓글 수: 2
Jan
2012년 9월 20일
Why do you delete your question? Then the work of the once, who wanted to help you, is lost. Not friendly.
Matt Fig
2012년 9월 21일
OP:
a part of my program has syntax that looks like this,
for n=1:1:A1 if (Z(n)<3 | Z(n)>9 | Z(n)~=Z(n)) disp('One or more of the element/s is/are not included.'); return;
elseif ~isnumeric(Z(n)) disp('There is error') return; end
so if i enter:
function_name ([3 4 A], [4 5 6])
matlab says: Undefined function or variable 'A'.
답변 (4개)
Wayne King
2012년 9월 20일
편집: Wayne King
2012년 9월 20일
MATLAB will do that on its own.
>> clear A % in case A is in the workspace
>> a=[1 2 A 4]
The MATLAB error message will be:
Undefined function or variable 'A'.
댓글 수: 1
Wayne King
2012년 9월 20일
If A is not a variable in the workspace, then inputting it into a function will cause an error
function sumout = testfunction(input1 )
sumout = sum(input1);
end
If you call that function with
>>sumout = testfunction([1 2 3 A 4]);
throws an error. You can always use isnumeric() if you want
if ~isnumeric(input)
error( )
end
댓글 수: 1
Jan
2012년 9월 20일
After A = 1; a = [1,2,A,4]; there is no method to detect, if a has been created using numbers, functions or other variables. When A is e.g. a character array, it is converted to double implicitly:
A = 'Z';
a = [1, 2, A, 4] % ==> [1, 2, 90, 4]
Here A is converted to the type DOUBLE and the ASCII value 90 is stored. Afterwards a is a double vector as all its elements have the same type.
I think, you have a different problem. Perhaps you want to test the class of A before inserting into the vector.
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