I want to remove some objects from a binary image based upon length to width ratio of the rectangular labeled each object, such that when a particular threshold is set the components satisfied then it removes t hose objects and show a new image.
Anybody has any idea?

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Adam Danz
Adam Danz 2019년 10월 18일
편집: Adam Danz 2019년 10월 18일

3 개 추천

Following similar logic to this answer, we'll use regionprops to get the length and width of the bounding box rectangles. Then we can compute the length:width ratio, set a threshold, and determine which boxes are greater than that threshold.
Then you can plot accepted objects with a red rectangle and rejected objects with a yellow rectangle.
See below for a second method.
% Read image as RGB
I = imread('bwimage.png'); %including the pull path is better
% Convert to binary
BW = imbinarize(rgb2gray(I));
% Get rid of white border
BWConv = bwconvhull(~BW);
BW = BW & BWConv;
% get region centers and major axis, and orientation
stats = regionprops('table',BW,'BoundingBox');
% Compute length/width ratio
stats.LenWdRatio = stats.BoundingBox(:,3) ./ stats.BoundingBox(:,4);
% Set threshold and determine which objects
% are greater than the threshold.
thresh = 2.0;
stats.isGreater = stats.LenWdRatio > thresh;
% Show bounding box for objects that met the threshold
figure()
h = imshow(BW);
axis on
hold on
% Plot red rectangles around accepted objects
arrayfun(@(i)rectangle('Position',stats.BoundingBox(i,:),'EdgeColor','r'), find(stats.isGreater));
% Plot yellow rectangles around rejected objects
arrayfun(@(i)rectangle('Position',stats.BoundingBox(i,:),'EdgeColor','y'), find(~stats.isGreater));
Second method: using major:minor axis length
Instead of using the horizontal and vertical extent of the bounding box, you could use the ratio of the MajorAxisLength to the MinorAxisLength. Here's an example why this method might be better. Suppose you have an long object that stretchs along a diagonal with slope=1. The width and height of the bounding box will be equal even though it's a very long and narrow object. If you used the ratio of the Major:Minor axis lengths, the object will be detected as long and narrow even through the bounding box is square.
To use this method, make the following changes.
% get region centers and major axis, and orientation
stats = regionprops('table',BW,'BoundingBox','MajorAxisLength','MinorAxisLength');
% Compute length/width ratio
stats.LenWdRatio = stats.MajorAxisLength ./ stats.MinorAxisLength;
[Update]
I forgot to show how to remove the objects.
When you call regionprop, add the SubarrayIdx property to the list.
stats = regionprops('table',BW,'BoundingBox','MajorAxisLength','MinorAxisLength','SubarrayIdx');
Then you can loop through each rejected object and replace its values in BW with false (black).
% Remove rejected objects (fill with black)
objRemoveIdx = find(~stats.isGreater);
for i = find(~stats.isGreater).'
BW(stats.SubarrayIdx{i,1},stats.SubarrayIdx{i,2}) = false;
end
% Show same figure with objects removed (yellow rectangles show where they were)
figure()
h = imshow(BW);
axis on
hold on
% Plot red rectangles around accepted objects
arrayfun(@(i)rectangle('Position',stats.BoundingBox(i,:),'EdgeColor','r'), find(stats.isGreater));
% Plot yellow rectangles around rejected objects
arrayfun(@(i)rectangle('Position',stats.BoundingBox(i,:),'EdgeColor','y'), find(~stats.isGreater));

댓글 수: 8

Image Analyst
Image Analyst 2019년 10월 18일
I think the second method is better. That's what I'd use. Bounding box is often deceptive, like when it's at an angle as you explained.
Adam Danz
Adam Danz 2019년 10월 18일
Thanks, @Image Analyst. The only reason I listed it as 2nd was because I thought of it and added it to the answer after the first method was posted.
Mustapha Seidu
Mustapha Seidu 2022년 2월 17일
Hi, I tried using this code but the line 'objRemoveIdx = find(~stats.isGreater). Returns an error " Requested array exceeds the maximum possible variable size." What could be the problem?
Adam Danz
Adam Danz 2022년 2월 22일
It looks like you're working with an image with lots of objects captured by regionprops, too many for Matlab to handle. Perhaps you could break up your image into smaller sub-images, if this is indeed the problem.
Image Analyst
Image Analyst 2022년 2월 22일
@Mustapha Seidu What is this stats structure? Is it something returned from regionprops()? I don't see any isGreater property that is measured by regionprops(). If you still have trouble, read this:
and then post your data and code in a new question (not here) in @Torkan's discussion.
See my Image Segmentation Tutorial here:
DGM
DGM 2022년 2월 23일
편집: DGM 2022년 2월 23일
Knowing what the rest of the error message says might also be helpful here.
I can run Adam's code out to 25 million objects before running into array size errors, and even then, they're not "maximum possible array size" errors; they're "maximum array size preferences" errors (I don't have much memory).
I question the likelihood that someone is ntentionally trying to segment images with tens of millions of objects in them. Any nontrivial images would need to be ridiculously large to even hold that many objects without them being connected.
Laura
Laura 2023년 3월 9일
@Adam Danz How can I use this code to select the large circles and worm shape objects in my figure in yellow?
Adam Danz
Adam Danz 2023년 3월 9일
@Laura the image you shared may be a bit difficult for this method but I would start by removing anything that isn't yellow-ish by looking at the color data and thresholding the colors. But since many of the yellow blobs do not appear to be discrete objects this method may fall short in which case asking a new question may get you more targetted help.

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