Could anyone suggest me is there any way of choosing maximum and minimum values together

조회 수: 1 (최근 30일)
A = [23 42 37 18 52];
With respect to command M = max(A) gives 52
min(A) gives 18
Is there any way so that i can get both 52 and 18 together(maximum and minimum together)
  댓글 수: 1
dpb 2019년 10월 17일
mnmx=[min(A) max(A)];
or write your own "syntactic sugar" routine minmax()--
function mnmx=minmax(x)
mnmx=[min(x(:)) max(x(:))];
The latter should probably also have the ability to return the locations to mimic builtin interfaces.....and maybe treat arrays the same as them also in working on column-basis by default with the dimension as the optional many choices to make.

댓글을 달려면 로그인하십시오.

답변 (3개)

Walter Roberson
Walter Roberson 2019년 10월 17일

Jos (10584)
Jos (10584) 2019년 10월 17일
Here is a nice trick that also allows you to combine functions in a single call, which also can return the other outputs of these functions:
minmaxFun = @(x) cellfun(@(F) F(x), {@min, @max}) ;
[V, I] = minmaxFun([2 1 3 5 2])
% V = [1 5], I = [2 4]
You can take this a step further:
mapF = @(val, fcns) cellfun(@(f) f(val{:}), fcns) ;
data = randi(10, [1 10])
[minmax, minmaxIDX] = mapF({data}, {@min @max})
S = mapF({data}, {@mean @median @std})
You can learn much more about this at Loren's Blog:

Daniel M
Daniel M 2019년 10월 17일
편집: Daniel M 2019년 10월 17일
A = [23 42 37 18 52];
minmaxVals = prctile(A,[0 100])
ans =
18 52
  댓글 수: 3
Walter Roberson
Walter Roberson 2019년 10월 17일
As I have been telling you: use the simple ways first and get them working, and do not worry about fancy ways until you have significant performance problems.
So just call min() and max() instead of spending a lot of time looking for a function that will return the values and indices. Or write a small function yourself that uses min and max internally to return what you want.

댓글을 달려면 로그인하십시오.


Help CenterFile Exchange에서 Matrix Indexing에 대해 자세히 알아보기


Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by