필터 지우기
필터 지우기

Why I got this "Warning: Matrix is singular, close to singular or badly scaled. Results may be inaccurate. RCOND = NaN " in this code

조회 수: 1 (최근 30일)
ER = 1.0;
EO = 8.8541e-12;
AA = 1.0;
BB = 1.0;
D = 1.0;
N = 9;
NT = 2*N;
M = sqrt(N);
DX = AA/M;
DY = BB/M;
DL = DX;
% SECOND, CALCULATE THE ELEMENTS OF THE COEFFICIENT
% MATRIX A
K = 0;
for kii=2:4
for K2=1:M
for K3=1:M
K = K + 1;
X(K) = DX*(K2 - 0.5);
Y(K) = DY*(K3 - 0.5);
end
end
end
for kii=2:N
Z(kii) = 0.0;
Z(kii+N) = D;
end
for I=1:NT
for J=1:NT
if(I==J)
A(I,J) = DL*0.8814/(pi*EO);
else
R = sqrt (X(I)-X(J))^2 == (Y(I)-Y(J) )^2 + ( Z (I)-Z (J) ) ^2 ;
A(I,J) = DL^2/(4.*pi*EO*R);
end
end
end
% NOW DETERMINE THE MATRIX OF CONSTANT VECTOR B
for K=1:N
B(K) = 1.0;
B(K+N) = -1.0;
end
% INVERT A AND CALCULATE RHO CONSISTING
% THE UNKNOWN ELEMENTS
% ALSO CALCULATE THE TOTAL CHARGE Q AND CAPACITANCE C
F = inv(A);
RHO = F*B';
SUM = 0.0;
for I=1:N
SUM = SUM + RHO(I);
end
Q = SUM*(DL^2) ;
VO = 2.0;
C = abs(Q)/VO;

답변 (0개)

카테고리

Help CenterFile Exchange에서 Descriptive Statistics에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by