how to replace the element with random number based if statement

조회 수: 1 (최근 30일)
Genz
Genz 2019년 10월 16일
댓글: sid Chen 2019년 10월 17일
Helllo everyone
i have a problem to change element of array with iteration approach. refer to https://www.mathworks.com/matlabcentral/answers/8817-how-to-replace-the-elements-of-a-matrix-using-the-conditions-if-else , i have same problem but little different. for instance i have mut1 = [.11 .12 .13 .14 .15 .16 .17 .18 .19 .20] and constan number 0.5. i want to replace element of mut1 with 'random number between' if random number(rmi) < 0.5. so this is what iam doing.
mutC = zeros(size(mut1));
pm = 0.5;
for i = 1:numel(mut1)
rmi = rand(1,1)
rCm = rbC+(raC-rbC).*rand(1,1)
if rmi<pm
mutC = rCm
else
mutC = mut1
end
end
but the final result is always mutC = mut1. there is no number from rCm.
I will appreciate any help. thank you.

채택된 답변

Andrei Bobrov
Andrei Bobrov 2019년 10월 16일
편집: Andrei Bobrov 2019년 10월 16일
mutC = mut1;
[m,n] = size(mut1);
pm = 0.5;
rmi = rand(m,n);
rCm = rbC+(raC-rbC).*rand(m,n);
for i = 1:numel(mut1)
if rmi(i) < pm
mutC(i) = rCm(i);
end
end
or
pm = .5;
mutC = mut1;
[m,n] = size(mut1);
rCm = rbC+(raC-rbC).*rand(m,n);
lo = rand(m,n) < pm;
mutC(lo) = rCm(lo);
  댓글 수: 3
Genz
Genz 2019년 10월 16일
many thanks sir. 2 thumbs up..
GBU.

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

sid Chen
sid Chen 2019년 10월 16일
Andrei Answer is very clear.
The problem is
if rmi<pm
mutC = rCm
else
mutC = mut1
with these code, you replace the whole matrix, all the elements are replaced.
To avoid this, you need to replace only one elements step by step. Just add an subscipt 'i' to point the element to be repalced.
if rmi<pm
mutC(i) = rCm(i)
else
mutC(i) = mut1(i)
  댓글 수: 2
Genz
Genz 2019년 10월 16일
when i run this code become error "index exceeds matrix dimensions"
sid Chen
sid Chen 2019년 10월 17일
if rmi<pm
mutC(i) = rCm % change here, rCm is a number,not a matrix
else
mutC(i) = mut1(i)

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Function Creation에 대해 자세히 알아보기

제품


릴리스

R2016b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by